The one line of symmetry is vertical, so we could fold the hexagon in half in such a way that the vertices A and B would meet at the same point, and the same goes for the pairs C,F and D,E. Because of this symmetry, we know angle AFE is congruent to BCD, and angle FED is congruent ot CDE.
Let <em>x</em> be the measure of angle CDE.
In any convex polygon with <em>n</em> sides, the interior angles sum to (<em>n</em> - 2)*180º in measure. ABCDEF is a hexagon, so <em>n</em> = 6.
We have 2 angles of measure 123º, 2 of measure <em>x</em>, and 2 of measure 2<em>x</em>. So
2(123º + <em>x</em> + 2<em>x</em> ) = (6 - 2)*180º
246º + 2<em>x</em> + 4<em>x</em> = 720º
6<em>x</em> = 474º
<em>x</em> = 79º
Angle AFE is congruent to angle BCD, which is twice the measure of CDE, so angle AFE has measure 2*79º = 158º.
Explanation:
f(x) = (x-4)(x+2)
1) For x-intercept, y will be 0
<u />
<u>x-intercept</u>: (4, 0), (-2, 0)
2) For vertex: x = -b/2a where ax² + bx + c
<u>Quadratic function</u>:
<u>vertex</u>:
y: (x-4)(x+2) = (1-4)(1+2) = -9
ordered pair of vertex: (1, -9)
3) For y-intercept, x will be 0
<u>y-intercept</u>: (0, -8)
Answer:
1.
2. Required factors: (x - 10) (x - 13)
x = 10, x = 13
Step-by-step explanation:
1.
Graph is intersecting x-axis at points (5, 0) & (11, 0)
Hence, x = 5 & x = 11 are zeroes of the function.
So, (x - 5) & (x - 11) are factors of the quadratic function:
Therefore, required function is:
![(x - 5)(x - 11) \\ = {x}^{2} - 11x - 5x + 55 \\ = {x}^{2} - 16x + 55](https://tex.z-dn.net/?f=%28x%20-%205%29%28x%20-%2011%29%20%5C%5C%20%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20-%2011x%20-%205x%20%2B%2055%20%5C%5C%20%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20-%2016x%20%2B%2055)
2.
Plug y = 0
So, x - 10 = 0, x - 13 =0
x = 10, x = 13
The answer is -91
hope this helps ;)
Column A
X=9
X=8
X=7
X=84
X=4 1/6