I think the answer is C 2/3
Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
-4g is what I got if ur evaluating
If it’s something about slope I got -4
Your answer is d, or the fourth option! hope this helped!
Answer:
Trinomial of degree 2
Step-by-step explanation:
The given expression cannot be reduce any further as far as number of terms (there are no like terms in it), so it is a trinomial.
Also, the largest power for the variable init (y) is the power 2, therefore it is a trinomial of degree 2.
