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VLD [36.1K]
3 years ago
15

PLEASW HELP DUE AT 9:20​

Mathematics
1 answer:
Bess [88]3 years ago
7 0

Answer:

1 x 10^10

2 x 10^-10

7 x 10^-11

8 x 10^-11

Step-by-step explanation:

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What is the value of v in the equation 3(2v + 1)=-15(5v + 16)​
Darina [25.2K]

Answer:

v = -3

Step-by-step explanation:

6v+3= -75v - 15 (16)

81v=  -243

then put it over -3 then

-243 over 81

7 0
4 years ago
Read 2 more answers
The integer between 42 and 140
Montano1993 [528]
It has 97 amounts.
43,44,45,46,47,48,49,50,
51,52,53,54,55,56,57,58,59,60
61,62,63,64,65,66,67,68,69,70 71,72,73,74,75,76,77,78,79,80
81,82,83,84,85,86,87,88,89,90
91,92,93,94,95,96,97,98,99,100
101,102,103,104,105,106,107,108,109,110
111,112,113,114,115,116,117,118,119,120
121,122,123,124,125,126,127,128,129,
130
131,132,133,134,135,136,137,138,139


Numbers between 42-140
6 0
3 years ago
The all-city chorus has raised $425 so far. To raise more money, the chorus is having a car wash and charging $10 per car. Which
beks73 [17]

Yo I have the same question eeek

8 0
3 years ago
CALCULUS EXPERT WANTED
Vlad [161]

a. Use the mean value theorem. 16 falls between 12 and 20, so

v'(16)\approx\dfrac{v(20)-v(12)}{20-12}=\dfrac{240-200}8=5

(Don't forget your units - 5 m/min^2)

b. v(t) gives the Johanna's velocity at time t. The magnitude of her velocity, or speed, is |v(t)|. Integrating this would tell us the total distance she has traveled whilst jogging.

The Riemann sum approximates the integral as

\displaystyle\int_0^{40}|v(t)|\,\mathrm dt=12\cdot200+8\cdot240+4\cdot220+16\cdot150=7600

If you're not sure how this is derived: we're given 5 sample points, so we can cut the interval [0, 40] into 4 subintervals. The lengths of each subinterval are 12, 8, 4, and 16 (the distances between each sample point), and the height of the rectangle approximating the area under the plot of |v(t)| is determined by the value of v(t) at each sample point, 200, 240, |-220| = 220, and 150.

c. Bob's velocity is given by B(t), so his acceleration is given by B'(t). We have

B'(t)=3t^2-12t

and at t=5 his acceleration is B'(5)=15 m/min^2.

d. Bob's average velocity over [0, 10] is given by the difference quotient,

\dfrac{B(10)-B(0)}{10-0}=\dfrac{700-300}{10}=40 m/min

6 0
4 years ago
What do you guys think?
Eva8 [605]
Correct answer is the one you put
8 0
3 years ago
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