F(x) = 5(-3x) ^2 - (-3x) + 1
f(x) = -8x ^2 + 3x + 1
f(x) = -8x ^3 + 3x
Answer:
Force = - 2.1 Newton
Step-by-step explanation:
According to question ,
The value of Spring constant , K = 7 N/m Newton per meter
And the spring is extended up to 0.3 meter
The Force experience on the spring is calculated from the Hook's Law
<u>The principal state that , the force applied on spring to extend or compress the spring to some distance is proportion to that distance. </u>
Let the force be F
So, F = - K X
where K is spring constant and X is its displacement
Negative sign shows displacement of spring once it is stretched
And K is spring constant
So ,Force = ( - ) 7 × 0.3
I.e Force = - 2.1 Newton Answer
Answer:
steps below
Step-by-step explanation:
3.2.1 AD = DB* sin 2 = DB * sin θ .. DE // AB ∠2= θ ... (1)
By laws of sines: DB / sin ∠5 = x / sin ∠4
∠4 = θ-α ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α
DB = (x*sin ∠5)/sin (θ-α)
= (x* sin (90°+α)) / sin (θ-α)
AD = DB*sinθ
= (x* sin (90°+α))*sinθ / sin (θ-α)
= x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α) .... sin90°=1, cos90°=0
= x* cosα* sinθ / sin (θ-α)
3.2.2 Please apply Laws of sines to calculate the length
Slope=-3/2
y-intercept=-7/2
Answer:
the answer is 60
Step-by-step explanation:
