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sammy [17]
2 years ago
12

5. A baker had 2 pans of corn bread. He served 1 1/4 pans. What fraction of a pan was left?

Mathematics
1 answer:
Ugo [173]2 years ago
4 0

Answer:

3/4 a pan

Step-by-step explanation:

2 - 1 1/4 = 3/4

two seperated into fourths would look like this

1/4 1/4 1/4 1/4

1/4 1/4 1/4 1/4

one seperated into fourths would look like this

1/4 1/4 1/4 1/4

so take one and one extra fourth away from two and you're left with

1/4 1/4 1/4

add that together and you have 3/4

You might be interested in
Solve the system of equations given . -2x+5y=-3
algol13

For this case we have the following system of equations:

-2x + 5y = -3\\y-15 = 3x

We multiply the second equation by -5:

-5y + 75 = -15x

Now we add the equations:

-2x-5y + 5y + 75 = -3-15x\\-2x + 75 = -3-15x\\-2x + 15x = -75-3\\13x = -78\\x = \frac {-78} {13}\\x = -6

We find the value of the variable "y":

y = 3x + 15\\y = 3 (-6) +15\\y = -18 + 15\\y = -3

THE solution is: (-6, -3)

Answer:

(-6, -3)

3 0
3 years ago
A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec
zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0
3 years ago
Line / goes through the Point 1-N-1) and is perpendicular to the line through (-6,5) and (-3,-2)
rosijanka [135]

Answer:

by using kinetic and potentail energy

7 0
2 years ago
Z
Anton [14]

Answer:

pa brainly po hehe need talaga points

3 0
2 years ago
1. 25.01 +36.5+ 200.35 =<br>(a) 81.545<br>(b) 228.91<br>(c) 229.01<br>(d) 261.41<br>(e) 261.86​
vesna_86 [32]

Answer:

The answer is e) 261.86

Step-by-step explanation:

25.01 +36.5+ 200.35

2 5 . 0 1

+ 3 6 . 5

2 0 0 . 3 5

_________

2 6 1 . 8 6

= 261.86

6 0
2 years ago
Read 2 more answers
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