The measure of angle APQ should be 90 degrees considering all the angles in a square add up to 360 degrees. NPQ should also be 90 degrees
Answer:
<u>Option C</u> is equal to 7^1/3
Option-B is correct that is y=f(x/-1) determines the reflection of the graph y=f(x) across the y-axis.
Given that,
The graph in black represents the y = f(x).
We have to pick the equation for the graph in red graph.
We know that,
The black graph is the graph of y=f(x).
The black graph is reflected across the y-axis in the red graph.
A. y=(x-1) determines the translation of the graph y=f(x) one unit to the right.
B. y=f(x/-1) determines the reflection of the graph y=f(x) across the y-axis.
C. y-1=f(x) determines the translation of the graph y=f(x) one unit up.
D. y/-1=f(x) determines the reflection of the graph y=f(x) across the y-axis.
Therefore, Option-B is correct that is y=f(x/-1) determines the reflection of the graph y=f(x) across the y-axis.
To learn more about graph visit: brainly.com/question/17267403
#SPJ9
Answer:
Step-by-step explanation:
2/3 cup is 1/4 of recipe to total, then X would be 4/4 of the recipe.
2/3 X
------ = --------
1/4 1
Cross multiply and you get x/4 = 2/3, simplfy to 3x=8, divide by 3 and you get 8/3 of a cup for the whole recipe. 8/3 is the same as 2 and 2/3 cup
Check the picture below.
well, the purple trapezoid, has a height of 5, and its bases are of 5 units and 8 units, recall the bases are the parallel sides in a trapezoid.
now, the yellow rectangle, is a 6x5, and it has those two green triangles in it, well, if we simply get the area of the rectangle, 30 anyway, and subtract the areas of those green triangles, what's leftover, is the rest of the shape on points DEFA.
keeping in mind that the green triangles have a base of 4 and a height of 3 for the one atop and base of 5 and height of 2 for the bottom one.
![\bf \stackrel{\textit{purple trapezoid}}{\cfrac{\stackrel{h}{5}(\stackrel{a}{5}+\stackrel{b}{8})}{2}}~~+~~\left[ \stackrel{\textit{yellow square}}{(6\cdot 5)}-\stackrel{\textit{two green triangles}}{\cfrac{1}{2}(4)(3)-\cfrac{1}{2}(5)(2)} \right] \\\\\\ \cfrac{5(13)}{2}+[30-6-5]\implies \cfrac{65}{2}+[19]\implies \cfrac{103}{2}\implies 51\frac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bpurple%20trapezoid%7D%7D%7B%5Ccfrac%7B%5Cstackrel%7Bh%7D%7B5%7D%28%5Cstackrel%7Ba%7D%7B5%7D%2B%5Cstackrel%7Bb%7D%7B8%7D%29%7D%7B2%7D%7D~~%2B~~%5Cleft%5B%20%5Cstackrel%7B%5Ctextit%7Byellow%20square%7D%7D%7B%286%5Ccdot%205%29%7D-%5Cstackrel%7B%5Ctextit%7Btwo%20green%20triangles%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%284%29%283%29-%5Ccfrac%7B1%7D%7B2%7D%285%29%282%29%7D%20%5Cright%5D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B5%2813%29%7D%7B2%7D%2B%5B30-6-5%5D%5Cimplies%20%5Ccfrac%7B65%7D%7B2%7D%2B%5B19%5D%5Cimplies%20%5Ccfrac%7B103%7D%7B2%7D%5Cimplies%2051%5Cfrac%7B1%7D%7B2%7D)