A rational function has no horizontal asymptote when the degree of the numerator is greater than the denominator.
In other words, where the numerator has a higher exponent than the denominator.
Answer:
C) exponent on top is 2, exponent on bottom is 1
I do A and B but that is the way I learned it. Hope this helps :)
For this case we have the following vertices:
D = (- 1, -1)
E = (1, -1)
F = (- 1, -6)
Then, the vertices after the transformation are:
D '= (- 1, 1)
E '= (1,1)
F '= (- 1,6)
The x coordinate remains the same
The y coordinate change sign.
Therefore, the transformation is:
Reflection on the x axis.
Answer:
Reflection on the x axis.
option 1
number 3 is your answer x<-y+4/2-4
Answer:
C
Step-by-step explanation: it's a negative slope, the y-intercept (b) is -1, and the rise over run is -4/1
