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aivan3 [116]
3 years ago
11

What are two ways that you can find the surface area of a prism

Mathematics
1 answer:
3241004551 [841]3 years ago
4 0

Answer:


Step-by-step explanation:


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Hello please help with my question, I will give brainlyest!
lilavasa [31]

No, John is incorrect.

<h3>Correct work shown:</h3>

\sf x^2 - 6x - 7 = 0

\sf x^2 - 6x = 7

\sf x^2 - 6x  + 9= 7 + 9

\sf (x-3)^2= 16

\sf x-3=\pm \sqrt{16}

\sf x-3= \pm 4

\sf x= + 4 + 3 \quad or \quad x = -4 + 3

\sf x= 7 \quad or \quad x = -1

The correct answer should be x = 7 or x = -1

3 0
1 year ago
Elija, Emily, Edward, and Esme each drew a conclusion about the figure below.
erik [133]
Please read the attached file

5 0
3 years ago
Read 2 more answers
Find the value of annuity if the periodic deposit is $250 at 5% compounded quarterly for 10 years
mylen [45]

Answer:

The value of  annuity is  P_v  =  \$ 7929.9

Step-by-step explanation:

From the question we are told that

    The periodic payment is  P  =  \$ 250

     The  interest rate  is   r =  5\%  =  0.05

     Frequency at which it occurs in a year is  n = 4 (quarterly )

      The number of years is  t =  10 \ years

The  value of the annuity is mathematically represented as

             P_v  =  P *  [1  - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ] (reference EDUCBA website)

 substituting values

             P_v  = 250 *  [1  - (1 + \frac{0.05}{4} )^{-10 * 4} ] * [\frac{(1 + \frac{0.05}{4} )}{ \frac{0.08}{4} } ]

             P_v  =  250 *  [1  - (1.0125 )^{-40} ] * [\frac{(1.0125 )}{0.0125} ]

             P_v  =  250 *  [0.3916 ] * [\frac{(1.0125)}{0.0125} ]

            P_v  =  \$ 7929.9

8 0
3 years ago
Plsss answer this rlly need dont answer this for just points plsss :(
klio [65]

1)V=Ixwxh

=5 cm x 3 cm x 2 cm

=30 cm³

2)V=bxh

=(10m x 6m) x 4m

= 60 m² x4 m

3)V=Ixwxh

=3 cm x 3 cm x 3 cm =27 cm³

=240 m³

4 0
1 year ago
11. Find the value of the expression: -7 + 11 - 6 + 8<br> Your answer
Dvinal [7]
The answer to -7 +11 -6 + 8 =6
6 0
3 years ago
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