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3 years ago

I need the volume of e and f

Mathematics

2 answers:

masya89 [10]3 years ago

6 0

Answer:

for e

$v = \frac{1}{ 2} \times 8 \times 7 \times 5.5 = 154$

for f

v=6×9×12=648

katovenus [111]3 years ago

5 0

Answer:

e-154

f-648

Step-by-step explanation:

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Round 6,311 to the nearest thousand

algol13

Answer:

6,000

Step-by-step explanation:

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3 years ago

A survey asks students who walk or ride a bike to school whether they live more than one

pshichka [43]

Answer:

Answer: The only correct option is the first one (top left)

Step-by-step explanation:

let's take each conclussion and see if it is true or not.

a) the number of students that live more than a mile away from school is 42

Of those, 32 ride a bike to reach the school.

The proportion is p = (32/42)*100% = 76

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3 years ago

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If one-sixth of a number plus one-third returns two-thirds of that number What is the number

Solnce55 [7]

Answer:

$x= \frac{2}{3}$

Step-by-step explanation:

Let the number be x

Given

$\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x$

Required

Find x

$\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x$

Collect Like Terms

$\frac{1}{6}x - \frac{2}{3}x = - \frac{1}{3}$

Take LCM

$\frac{1 - 4}{6}x = \frac{-1}{3}$

$\frac{- 3}{6}x = \frac{-1}{3}$

Multiply both sides by 6

$6 * \frac{- 3}{6}x = \frac{-1}{3} * 6$

$-3x= -2$

Divide both sides by -3

$\frac{-3x}{-3}= \frac{-2}{-3}$

$x= \frac{2}{3}$

Hence, the number is $\frac{2}{3}$

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4 years ago

If the expression x^{-\frac{3}{2}}y\sqrt{36xy^2}x − 2 3 y 36xy 2 is written in the form ax^by^cax b y c , then what is the p

Mekhanik [1.2K]

Answer:

-12

Step-by-step explanation:

The given expression is

$x^{-\frac{3}{2}}y\sqrt{36xy^2}$

We have to rewrite the given function in the form of

$ax^{b}y^c$ ....(i)

then we have to find the product of a,b and c.

The given expression can be rewritten as

$x^{-\frac{3}{2}}y\sqrt{36}\sqrt{x}\sqrt{y^2}$

Using properties of exponents we get

$x^{-\frac{3}{2}}y6x^{\frac{1}{2}}y$ $[\because \sqrt[n]{a}=a^{\frac{1}{n}}]$

$6x^{-\frac{3}{2}+\frac{1}{2}}y^{1+1}$ $[\because a^ma^n=a^{m+n}]$

$6x^{-1}y^{2}$ ...(ii)

On comparing (i) and (ii), we get

$a=6,b=-1,c=2$

Product of a,b and c is

$abc=(6)(-1)(2)=-12$

Therefore, the product of a,b, and c is -12.

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4 years ago

HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!1

erastovalidia [21]

i don't really know the answer to that but if you stick to it you will increase you're knowledge. good luck!

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4 years ago

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