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Gala2k [10]
3 years ago
6

N^2-8n=0 can i have the work shown?

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

n=1/8N^2

Step-by-step explanation:

n^2-8n=0

-8n=-N^2

n=1/8N^2

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In 12 hours, the temperature fell steadily from 17degrees to -7degrees f. what was the average change in temperature per hour?
Zarrin [17]
If the temperature changed from 17 degree F to -7 , the change was
17+7=24 degrees F
the average change was 24/12=2 , 2 degrees per hour 
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7 0
3 years ago
Brooke saved the same amount of money each week for four weeks. She made this table to show how much money she saved.
Musya8 [376]

Answer:

In 10 weeks of time, Brooke would  earn $ 20.

Step-by-step explanation:

Here, according to the table:

The money saved in week 1   =  $ 2   =   $(1  x 2)

The money saved in week 2  =  $ 4   =  $ ( 2 x 2)

The money saved in week 3   =  $ 6  =  $ ( 3 x 2)

The money saved in week 4   =  $ 8 =   $ ( 4 x 2)

So, by the graph relation, we can see that:

The amount saved in n weeks = ( n x 2) dollars

So, the amount saved by Brooke in 10 weeks is:

Put n =  10, we get:

The money saved  = 2 n = 2 x 10 = $ 20

Hence, in 10 weeks of time, Brooke would  earn $ 20.

5 0
3 years ago
PLEASE HELP ASAP! WILL GIVE BRAINLIEST! Thank you!<br> Given: mKP=2mIP, mIVK=120°<br> Find: m∠KJL
shtirl [24]

That is 99 degrees if you have the triangle facing the other way

8 0
3 years ago
In a binomial experiment with 45 trials, the probability of more than 25 success can be approximated by What is the probability
Pani-rosa [81]

Answer:

0.6 is the probability of success of a single trial of the experiment

Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by P(Z>\frac{(25-27)}{3.29})

What is the probability of success of a single trial of this experiment?

Options:

  • 0.07
  • 0.56
  • 0.79
  • 0.6

Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

\mu =\frac{np}{\sigma}=\sqrt{np(1-p)}

now,

Z=\frac{X-\mu}{\sigma}

so,

by comparing with P(Z>\frac{(25-27)}{3.29}), we get:

μ=np=27

\sigma=\sqrt{np(1-p)} =3.29

put np=27

we get:

\sigma=\sqrt{27(1-p)} =3.29

take square on both sides:

10.8241=27-27p

27p=27-10.8241

p=0.6

Which is the probability of success of a single trial of the experiment

5 0
3 years ago
Lim x tends to π÷2 , then what is the value of (tanx + cotx) ÷ ( tanx - cotx)​
KiRa [710]

(tan(<em>x</em>) + cot(<em>x</em>)) / (tan(<em>x</em>) - cot(<em>x</em>)) = (tan²(<em>x</em>) + 1) / (tan²(<em>x</em>) - 1)

… = (sin²(<em>x</em>) + cos²(<em>x</em>)) / (sin²(<em>x</em>) - cos²(<em>x</em>))

… = -1/cos(2<em>x</em>)

Then as <em>x</em> approaches <em>π</em>/2, the limit is -1/cos(2•<em>π</em>/2) = -sec(<em>π</em>) = 1.

8 0
2 years ago
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