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3 years ago

N^2-8n=0 can i have the work shown?

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

8 0

Answer:

n=1/8N^2

Step-by-step explanation:

n^2-8n=0

-8n=-N^2

n=1/8N^2

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In 12 hours, the temperature fell steadily from 17degrees to -7degrees f. what was the average change in temperature per hour?

Zarrin [17]

If the temperature changed from 17 degree F to -7 , the change was
17+7=24 degrees F
the average change was 24/12=2 , 2 degrees per hour

7 0

3 years ago

Brooke saved the same amount of money each week for four weeks. She made this table to show how much money she saved.

Musya8 [376]

Answer:

In 10 weeks of time, Brooke would earn $ 20.

Step-by-step explanation:

Here, according to the table:

The money saved in week 1 = $ 2 = $(1 x 2)

The money saved in week 2 = $ 4 = $ ( 2 x 2)

The money saved in week 3 = $ 6 = $ ( 3 x 2)

The money saved in week 4 = $ 8 = $ ( 4 x 2)

So, by the graph relation, we can see that:

The amount saved in n weeks = ( n x 2) dollars

So, the amount saved by Brooke in 10 weeks is:

Put n = 10, we get:

The money saved = 2 n = 2 x 10 = $ 20

Hence, in 10 weeks of time, Brooke would earn $ 20.

5 0

3 years ago

PLEASE HELP ASAP! WILL GIVE BRAINLIEST! Thank you! Given: mKP=2mIP, mIVK=120° Find: m∠KJL

shtirl [24]

That is 99 degrees if you have the triangle facing the other way

8 0

3 years ago

In a binomial experiment with 45 trials, the probability of more than 25 success can be approximated by What is the probability

Pani-rosa [81]

Answer:

0.6 is the probability of success of a single trial of the experiment

Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by $P(Z>\frac{(25-27)}{3.29})$

What is the probability of success of a single trial of this experiment?

Options:

0.07
0.56
0.79
0.6

Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

$\mu =\frac{np}{\sigma}$ = $\sqrt{np(1-p)}$

now,

$Z=\frac{X-\mu}{\sigma}$

so,

by comparing with $P(Z>\frac{(25-27)}{3.29})$ , we get:

μ=np=27

$\sigma=\sqrt{np(1-p)}$ =3.29

put np=27

we get:

$\sigma=\sqrt{27(1-p)}$ =3.29

take square on both sides:

10.8241=27-27p

27p=27-10.8241

p=0.6

Which is the probability of success of a single trial of the experiment

5 0

3 years ago

Lim x tends to π÷2 , then what is the value of (tanx + cotx) ÷ ( tanx - cotx)

KiRa [710]

(tan(x) + cot(x)) / (tan(x) - cot(x)) = (tan²(x) + 1) / (tan²(x) - 1)

… = (sin²(x) + cos²(x)) / (sin²(x) - cos²(x))

… = -1/cos(2x)

Then as x approaches π/2, the limit is -1/cos(2•π/2) = -sec(π) = 1.

8 0

2 years ago