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2 years ago

NI LINKS OR ELSE YOU'LL BE REPORTED! Please give me the correct answer.Only answer if you're very good at Math.

Mathematics

1 answer:

QveST [7]2 years ago

8 0

Answer:

3 ballons

Step-by-step explanation:

3 ballons is the answer

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Can someone help me with this<br> S=?

MAXImum [283]

Answer:

In order to find the value of s, we must isolate the s variable in this equation, so the first step should be subtracting 3 5/6 from both sides of this equation. In order to subtract, we multiply each denominator to get 42, and multiply the numerator by the same amount, and subtract the number from both sides:

s + 3 35/42 = 9 6/42

s = 5 13/42

Step-by-step explanation:

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2 years ago

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2 years ago

What is the prime factorization of 152

MakcuM [25]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 43 ft/s. Its height

Lina20 [59]

Answer:

Instantaneous Velocity at t = 1 is 20 feet per second

Step-by-step explanation:

We are given he following information in the question:

$y(t)=43t-23t^{2}$

B) Instantaneous Velocity at t = 1

$y(1) = 43(1)-23(1)^2 = 20$

A) Formula:

Average velocity =

$\displaystyle\frac{\text{Displacement}}{\text{Time}}$

1) 0.01

$y(1 + 0.01)=y(1.01) = 43(1.01)-23(1.01)^{2} = 19.9677\\\\\text{Average Velocity} = \dfrac{y(1.01)-y(1)}{1.01-1} =\dfrac{19.9677-20}{1.01-1}= \dfrac{-0.0323}{0.01} = -3.230000 \text{feet per second}$

2) 0.005 s

$y(1 + 0.005)=y(1.005) = 43(1.005)-23(1.005)^{2} = 19.984425\\\\\text{Average Velocity} = \dfrac{y(1.005)-y(1)}{1.005-1} =\dfrac{19.984425-20}{1.005-1} = -3.1150000 \text{feet per second}$

3) 0.002 s

$y(1 + 0.002)=y(1.002) = 43(1.002)-23(1.002)^{2} = 19.993908\\\\\text{Average Velocity} = \dfrac{y(1.002)-y(1)}{1.002-1} =\dfrac{19.993908-20}{1.002-1} = -3.0460000 \text{feet per second}$

4) 0.001 s

$y(1 + 0.001)=y(1.001) = 43(1.001)-23(1.001)^{2} = 19.996977\\\\\text{Average Velocity} = \dfrac{y(1.001)-y(1)}{1.001-1} =\frac{19.996977-20}{1.001-1} = -3.0230000 \text{feet per second}$

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2 years ago

At midnight the temperature was -8 degree F. At noon the Temperature was 23 degrees F. Which expression represents the increase

Firlakuza [10]

23- -8

This equals to 31. 31 degrees was the increase

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2 years ago