$<br> 20,524,945,000,000 rounded to the nearest billion

At a football game a vender sold a combined total of 240 sodas and hot dogs the number of sodas sold was three times the number

Sidana [21]

Answer:

60 hot dogs and 180 soda

Step-by-step explanation:

Soda was sold 3 times the number of hot dogs, and there were 240 in total.

So the equation would be:

3x + x = 240

3x being the number of soda and x being the number of hot dogs which like i sad earlier adds up to 240.

3x + x = 240

4x = 240

x= 60

60 being the amount of hot dogs and 3 time of soda would be 180 and adding them both up would be 240

8 0

2 years ago

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What is the effect on the graph of the parent function f(x) = x when f(x) is changed to x + 6?

Zolol [24]

I don't know if I'm right the answer could be 6x

6 0

2 years ago

Read 2 more answers

Wich situation can NOT represent a proportional relationship

aliya0001 [1]

Answer:

We need an image or more info

Step-by-step explanation:

8 0

2 years ago

Which of the following functions has a graph that is a line? f(x) = |x| f(x) = x f(x) = x 2

sattari [20]

Answer:

f(x) = x

Step-by-step explanation:

f(x) = |x| will give you V graph

f(x) = x will give you line graph (linear)

f(x) = x² will give you a curve graph

7 0

3 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 420 green peas and 174 yellow peas. Use a 0.01

slavikrds [6]

Answer:

a) $z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649$

b) For this case we need to find a critical value that accumulates $\alpha/2$ of the area on each tail, we know that $\alpha=0.01$ , so then $\alpha/2 =0.005$ , using the normal standard table or excel we see that:

$z_{crit}= \pm 2.58$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

Step-by-step explanation:

Data given and notation

n=420+174=594 represent the random sample taken

X=174 represent the number of yellow peas

$\hat p=\frac{174}{594}=0.293$ estimated proportion of yellow peas

$p_o=0.23$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of yellow peas is 0.23:

Null hypothesis: $p=0.23$

Alternative hypothesis: $p \neq 0.23$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>3.649)=0.00026$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

b) Critical value

For this case we need to find a critical value that accumulates $\alpha/2$ of the area on each tail, we know that $\alpha=0.01$ , so then $\alpha/2 =0.005$ , using the normal standard table or excel we see that:

$z_{crit}= \pm 2.58$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

5 0

3 years ago

$ 20,524,945,000,000 rounded to the nearest billion