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vlada-n [284]
3 years ago
13

All repeating decimals are irrational True or false

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
8 0

Answer: the answer is true sorry if its wrong

Step-by-step explanation:

have a nice day buddy

lesantik [10]3 years ago
6 0

Answer:

True

Step-by-step explanation:

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What are the factors of m^2-12m+20
Juli2301 [7.4K]

Answer:

(m - 10)(m - 2)

Step-by-step explanation:

We need 2 numbers whose product is + 20 and whose sum = -12. They are -10 and -2.  These go into the 2 parentheses:

(m - 10)( m - 2).

4 0
3 years ago
Read 2 more answers
-2.7f + 0.3f - 16 - 4=
suter [353]

Answer:

-2.4f or -8 1/3

Step-by-step explanation:

I am not sure what should be at the end of the equal sign but if it is to simplify it would be -2.4f-20

If you want to solve then you get -2.4f=20 so f=-20/2.4 which equal to -8 1/3

3 0
2 years ago
Please help me with this question, I'm stuck ;( .
sveticcg [70]

i think C but i dont know forsure

7 0
3 years ago
Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t
Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

\frac{dy}{dx}=0 (The slope is zero)

--To obtain vertical tangent lines, the condition is:

\frac{dy}{dx}=\frac{1}{0} (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}=2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0

Solving for dy/dx:

\frac{dy}{dx}(-2x+2y-8)=-2x+2y-4\\\frac{dy}{dx}=\frac{2y-2x-4}{2y-2x-8}

Applying the first conditon (slope is zero)

\frac{2y-2x-4}{2y-2x-8}=0\\2y-2x-4=0

Solving for y (Adding 2x+4, dividing by 2)

y=x+2 (I)

Replacing (I) in the given equation:

x^{2}-2x(x+2)+(x+2)^{2}+4x-8(x+2)+20=0\\x^{2}-2x^{2}-4x+x^{2} +4x+4+4x-8x-16+20=0\\-4x+8=0\\x=2

Replacing it in (I)

y=(2)+2

y=4

Therefore, the parabola has a horizontal tangent line at the point (2,4)

Applying the second condition (slope is undefined where denominator is zero)

2y-2x-8=0

Adding 2x+8 both sides and dividing by 2:

y=x+4(II)

Replacing (II) in the given equation:

x^{2}-2x(x+4)+(x+4)^{2}+4x-8(x+4)+20=0\\x^{2}-2x^{2}-8x+x^{2}+8x+16+4x-8x-32+20=0\\-4x+4=0\\x=1

Replacing it in (II)

y=1+4

y=5

The parabola has vertical tangent lines at the point (1,5)

4 0
3 years ago
Simplify. 1/4y+1 1/2+2−1 3/4y−12 Enter your answer in the box.
docker41 [41]

Answer:

-3y + -9/2

Step-by-step explanation:

6 0
3 years ago
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