Answer:
-5
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
45−(5+8y−3(y+3))=−3(3y−5)−(5(y−1)−2y+6)
45+−1(5+8y−3(y+3))=−3(3y−5)+−1(5(y−1)−2y+6)(Distribute the Negative Sign)
45+(−1)(5)+−1(8y)+−1(−3(y+3))=−3(3y−5)+−1(5(y−1))+−1(−2y)+(−1)(6)
45+−5+−8y+3y+9=−3(3y−5)+−5y+5+2y+−6
45+−5+−8y+3y+9=(−3)(3y)+(−3)(−5)+−5y+5+2y+−6(Distribute)
45+−5+−8y+3y+9=−9y+15+−5y+5+2y+−6
(−8y+3y)+(45+−5+9)=(−9y+−5y+2y)+(15+5+−6)(Combine Like Terms)
−5y+49=−12y+14
−5y+49=−12y+14
Step 2: Add 12y to both sides.
−5y+49+12y=−12y+14+12y
7y+49=14
Step 3: Subtract 49 from both sides.
7y+49−49=14−49
7y=−35
Step 4: Divide both sides by 7.
7y
7
=
−35
7
y=−5
Answer:
I belive it would be HL because its defenitly not SSS
Step-by-step explanation:
HL Postulate is if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.
Step-by-step explanation:
x= -2,
(x - 5) / 2= -6
( (-2) - 5) / 2= -6
(-7) / 2 = -6
-3.5 = - 6
right hand side not equal to left hand side of this equation.so,x= -2 cannot exist for this equation.
x=2,
(x - 5) / 2= -6
(2 - 5) / 2= -6
(-3) / 2= -6
-1.5 = - 6
right hand side not equal to left hand side of this equation.so,x= 2 cannot exist for this equation.
x= -17
(x - 5) / 2= -6
( ( -17) - 5) / 2= -6
(- 22) / 2= -6
-11 = -6
right hand side not equal to left hand side of this equation.so,x= -17 cannot exist for this equation.
x= -7,
(x - 5) / 2= -6
( ( -7) -5) / 2= -6
(-12) / 2= -6
-6= -6
right hand side equal to left hand side of this equation.so,x= -7 exist for this equation.
18bags
Look if 1=3 2=9 3= 18 so he uses 18 bags!
