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liraira [26]
3 years ago
14

Solve 1/2n +3 < 5. Which graph shows the solutions​

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:

last one

hope it helps..

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I need help asapp!!!!!!!
labwork [276]

Answer:

Step-by-step explanation:

As per midsegment theorem of a trapezoid,

Segment joining the midpoints of the legs of the of the trapezoid is parallel to the bases and measure half of their sum.

Length of midsegment = \frac{1}{2}(b_1+b_2)

3). MN = \frac{1}{2}(18+10)

           = 14

4). MN = \frac{1}{2}(57+76)

           = 66.5

5). MN = \frac{1}{2}(AB+DC)

    7 = \frac{1}{2}(AB+10)

    14 = AB + 10

    AB = 14 - 10

    AB = 4

6). 15 = \frac{1}{2}[(3x+2)+(2x-2)]

    30 = 5x

     x = 6

4 0
3 years ago
Solve for x??<br><br><br>please help me with this....​
Ainat [17]

Answer:

C. 5

Step-by-step explanation:

a triangle has 180 degrees as shown 1 angle has 88 degrees and the other 2 angles are equal basically divide 92 by 2 and you would get 46 then do that reverse thingy subtract the 1 and get 45 the divide 45 by 9 and get 5

Its C.

8 0
3 years ago
Read 2 more answers
Find X (Show Your Work)<br> WILL MARK BRAINLIEST!
Rudiy27

Answer:

its 8 cause 2 times x is 40 40+-40= 0 so 2 times 4 is 8

Step-by-step explanation:

6 0
3 years ago
2+2 my question must be 20 characters long
geniusboy [140]
It is four. So two and two you add them together to be four. Good job. Your learning :)
4 0
3 years ago
A lighthouse is built on an exposed reef, 4.5 miles off-shore. The shoreline is perfectly straight, and a town is located 6 mile
Alisiya [41]

Answer: 3.94 hours

Step-by-step explanation:

From the question, the following parameters are given:

Distance offshore = 4.5 miles

Distance downshore = 6 miles

Speed when running = 3.4 mph

Speed with boat = 1.8 mph

distance of boat rowing = sqrt(4.5^2 + x^2)

Where

Speed = distance/time

Time = distance/speed

Time = distance of boat rowing/1.8

distance of running = 6 - x

Time = (6-x)/3.4

total travel time

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

dt/dx = x/(1.8×sqrt(4.5^2 + x^2) - 1/3.4

d^2t/dx^2 = +ve at any x

x is at its minimum when dt/dx=0

x/(1.8×sqrt(4.5^2 + x^2) = 1/3.4

x = 6/sqrt(253) × 4.5 = 1.697 miles

Substitute x in

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

We obtaine

t = sqrt(4.5^2 + 1.697^2)/1.8 + (6 - 1.69)/3.4

t = 2.672+ 1.266 = 3.94 hours

7 0
3 years ago
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