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Bas_tet [7]
2 years ago
10

It costs y dollars to buy x cans of tomatoes. What is the constant of proportionality?

Mathematics
1 answer:
svlad2 [7]2 years ago
6 0

Answer

1 and 0.89

Step-by-step explanation:

idrk tho

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Factor completely 2x2 − 2x − 40
Montano1993 [528]

Answer:

2(x-5)(x+4)

Step-by-step explanation:

2x^2 − 2x − 40

Factor out a 2

2(x^2 -x -20)

What 2 numbers multiply to -20 and add to -1

-5*4 = -20

-5+4 = -1

2(x-5)(x+4)

4 0
3 years ago
it takes about me 25 minutes to make out a test for a mathamatics class. How long will it take to make out tests for all fve of
Elza [17]
150 minutes of mathmatices class
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3 years ago
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Find 3 different fraction equivalent to 8/9
Solnce55 [7]
Three fractions that are equivalent to 8/9 are 16/18, 24/27, and 32/36. 

Best of luck, friend. 
3 0
3 years ago
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Two lamps marked 100 W - 110 V and 100 W - 220 V are connected i
ELEN [110]
<h2>Answer:</h2>

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

<h2>Step-by-step explanation:</h2>

Given:

<em>First lamp rating</em>

Power (P) = 100W

Voltage (V) = 110V

<em>Second lamp rating</em>

Power (P) = 100W

Voltage (V) = 220V

<em>Source</em>

Voltage = 220V

i. <u>Get the resistance of each lamp</u>.

Remember that power (P) of each of the lamps is given by the quotient of the square of their voltage ratings (V) and their resistances (R). i.e

P = \frac{V^2}{R}

<em>Make R subject of the formula</em>

⇒ R = \frac{V^2}{P}             ------------------(i)

<em />

<em>For first lamp, let the resistance be R₁. Now substitute R = R₁, V = 110V and P = 100W into equation (i)</em>

R₁ = \frac{110^2}{100}

R₁ = 121Ω

<em />

<em>For second lamp, let the resistance be R₂. Now substitute R = R₂, V = 220V and P = 100W into equation (i)</em>

R₂ = \frac{220^2}{100}

R₂ = 484Ω

<em />

<em />

ii.<u> Get the equivalent resistance of the resistances of the lamps.</u>

Since the lamps are connected in series, their equivalent resistance (R) is the sum of their individual resistances. i.e

R = R₁ + R₂

R  = 121 + 484

R = 605Ω

iii. <u>Get the current flowing through each of the lamps. </u>

Since the lamps are connected in series, then the same current flows through them. This current (I) is produced by the source voltage (V = 220V) of the line and their equivalent resistance (R = 605Ω). i.e

V = IR [From Ohm's law]

I = \frac{V}{R}

I = \frac{220}{605}

I = 0.36A

iv. <u>Get the power consumed by each lamp.</u>

From Ohm's law, the power consumed is given by;

P = I²R

Where;

I = current flowing through the lamp

R = resistance of the lamp.

<em>For the first lamp, power consumed is given by;</em>

P = I²R           [Where I = 0.36 and R = 121Ω]

P = (0.36)² x 121

P = 15.68W

<em>For the second lamp, power consumed is given by;</em>

P = I²R           [Where I = 0.36 and R = 484Ω]

P = (0.36)² x 484

P = 62.73W

Therefore;

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

8 0
3 years ago
Given f (x) = -3 + 5, solve for x when f (x) = -4
bezimeni [28]

The value of x when f(x) = -4 is 3

<h3>How to solve the function?</h3>

The function is given as:

f(x) = -3x + 5

When f(x) = -4, we have:

-4 = -3x + 5

Subtract 5 from both sides

-3x = -9

Divide both sides by -3

x = 3

Hence, the value of x when f(x) = -4 is 3

Read more about functions at:

brainly.com/question/4025726

#SPJ1

4 0
1 year ago
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