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Arte-miy333 [17]
3 years ago
9

You have a new job where you earn 13% commission in addition to $5.25 per hour. On your first day, you work for 7.75 h and sell

$95.20 worth of merchandise. How much money did you make
Mathematics
1 answer:
satela [25.4K]3 years ago
3 0

You would make $53.07.

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Answer:

E And d

Step-by-step explanation:

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LuckyWell [14K]

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240 units I think

Step-by-step explanation

20 by 2 equal 10 you now know the triangle length

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20 X 10 equal 200 length of rectangle add both and equal 240.

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Peter practice violin for a total of 55 minutes over the weekend he practice 25 minutes on Saturday how many minutes does he pra
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  • Peter practices for 30 minutes on Sunday.
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3 years ago
Need Help With Math. One Question
alina1380 [7]

Answer: 2 < x < 16

The triangle inequality theorem says that if we have a triangle with sides a,b,c then

b-a < c < b+a

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In this case, a = 7 and b = 9 and c = x

so we have

b-a < c < b+a

9-7 < c < 9+7 .... replace a with 7, replace b with 9

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2 < x < 16 .... replace c with x

So x can be any number between 2 and 16. The value of x cannot be equal to 2. Also, x cannot be equal to 16 either.

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4 years ago
1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

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