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Dafna1 [17]
3 years ago
12

Simplify. 14a^2bc^4/21abc^6

Mathematics
2 answers:
kramer3 years ago
7 0
14a^2bc^4/21abc^6 = 2a/3b^2
vagabundo [1.1K]3 years ago
7 0

Answer:

Step-by-step explanation:

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Answer:

x = 44

Step-by-step explanation:

sqrt(x+5) -3 =4

Add 3 to each side

sqrt(x+5) -3+3 =4+3

sqrt(x+5)  =7

Square each side

(sqrt(x+5))^2  =7^2

x+5 = 49

Subtract 5 from each side

x+5-5 = 49-5

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3 years ago
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Answer:

y = x/2 + 5

Step-by-step explanation:

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To solve this problem you must apply the proccedure shown below:
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5 0
3 years ago
Use the function below to find F(3). <br><br> F(x) = 4(1/3)^x​
aalyn [17]

Answer:

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F(3) = 4(1/3)^3

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Then multiply

f(3) = 4/27

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3 years ago
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Ok did your teacher say anything about not being able to use negative numbers or fractions? If not can you use fractions or negative numbers.
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