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4 years ago

Write 5,382 in expanded form using exponents

Mathematics

1 answer:

ohaa [14]4 years ago

3 0

(5 x 1000) + (3 x 100) + (8 x 10) + (2 x 1)

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Determine if the sequence below is arithmetic or geometric and determine the common difference/ratio in simplest form.

Nana76 [90]

Step-by-step explanation:

this is clearly not a linear sequence (the terms don't have the same difference).

so, it has to be a geometric sequence.

the common ratio is r.

s2 = s1 × r

16 = 64 × r

r = 16/64 = 1/4

control :

s3 = s2×r

4 = 16 × 1/4 = 4

correct.

6 0

2 years ago

Rewrite the expression in terms of ln 4 and ln 5.<br> ln(400)

Rzqust [24]

4x5x20 hope that helps

8 0

3 years ago

Rewrite the expression with a rational exponent as a radical expression.

Nuetrik [128]

Answer:

Rewriting the expression $(3^\frac{2}{3})^\frac{1}{6}$ with a rational exponent as a radical expression we get $\mathbf{\sqrt[9]{3} }$

Step-by-step explanation:

We need to rewrite the expression $(3^\frac{2}{3})^\frac{1}{6}$ with a rational exponent as a radical expression.

The expression given is:

$(3^\frac{2}{3})^\frac{1}{6}$

First we will simply the expression using exponent rule $(a^m)^n=a^{mn}$

$(3^\frac{2}{3})^\frac{1}{6}\\=(3^\frac{2}{18})$

As we know 2 and 18 are both divisible by 2, we can write

$=(3^\frac{1}{9})$

Now we know that $a^\frac{1}{9}=\sqrt[9]{a}$

Using this we get

$=\sqrt[9]{3}$

So, rewriting the expression $(3^\frac{2}{3})^\frac{1}{6}$ with a rational exponent as a radical expression we get $\mathbf{\sqrt[9]{3} }$

3 0

3 years ago

14 B. Bernard has 21 pages of research paper due by Friday. If he starts on Tuesday, how many pages does he need to do per day?

OLga [1]

Answer:

Step-by-step explanation:

Due Friday we have 3 days (Tuesday, Wednesday, Thursday)

21/3 = 7

8 0

3 years ago

Simplify. 8u + 9u + 3u - 5u What is the answer?

Helga [31]

Simplify the expression
25u

To find the what answer it is:
Do 11 + 14 = 25
so u = 25 or 25u

Answer: 11u + 14v
Hope this helps! :)

7 0

4 years ago