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2 answers:
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Answer:
p(x) = 0.1x + 1
Step-by-step explanation:
Pressure at sea level = 1 atmosphere
Depth dove by Sydney = 23 meters
Pressure at a depth of 23 meters = 3.3 atmospheres
So,
Pressure at a depth of 23 meters = Pressure at sea level + k * Depth dove by Sydney
where k is the diving rate constant
=> 3.3 = 1 + k(23)
=> 3.3 = 23k + 1
Subtracting 1 from both the sides, we get
3.3 - 1 = 23k + 1 -1
Cancelling out the +1 and -1 from the right side, we get
2.3 = 23k
=> 23k = 2.3
Dividing both sides by 23, we get
Cancelling out the 23's from the top and bottom of the left side, we have
k = 0.1
Plugging in the value of k in the equation, we get
Pressure at a particular depth = Pressure at sea level + k * Depth dove by Sydney
p(x) = 1 + k(x) [where p(x) is the pressure at a depth x]
=> p(x) = 1 + 0.1(x)
=> p(x) = 0.1x + 1
Answer:
First page
a: 0.864
b: x = 7, -8.75
Second page:
Domain: (3, ∞)
Range: (-∞, ∞)
Asymptote: x = 3
Third page: About 464 visitors
Step-by-step explanation:
See first attached photo for page 1 work
Second page: A log argument must be positive (the number in the log x place), so and number for x greater than 3 will satisfy this requirement.
x - 3 > 0, so x > 3
The range of a log x fucntion is (-∞, ∞),
Since x ≠ 3, there is a vertical asymptote at x = 3, the graph will not cross the line x = 3
*See second attached photo for the graph
Third page: Take the visitors of one year, and divide it by the visitors of the previous year to determine the % growth.
EX: from 2003 to 2004 the number of visitors grew from 310 to 322, a % change of
322/310 = 1.07, or 7%
Do this will all the years and you will see that each year there was about a 7% growth.
So in year 2009, there will be 434(1.07) = 464.38 visitors, or about 464 visitors
