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jok3333 [9.3K]
3 years ago
7

Help me im dumb and tired

Mathematics
2 answers:
vlabodo [156]3 years ago
7 0

Answer:

C is correct hun. :)

Step-by-step explanation:

Nina [5.8K]3 years ago
4 0

Answer:

23/6

Step-by-step explanation:

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Need answer ASAP! Please see screen shot.
vivado [14]

Answer:

0.4 or \frac{2}{5}

Step-by-step explanation:

James spun the arrow 30 times which means 30 is the total. In other words, it's your denominator (\frac{x}{30}). It landed on the blue section 12 times which means 12 is the part of the whole. In other words, it's your numerator (\frac{12}{y}). Plug in the entire fraction and you get \frac{12}{30}. Divide 12 by 30 and you get 0.4 or if you divide both the numerator & denominator by 6, you get \frac{2}{5}. Either one works, depending on what your question asks for.

6 0
3 years ago
In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
3 years ago
Question 9 (3 points)
Mila [183]

From the dot plot, we have that 90.91% of the students have 5 or more vowels in their first and last  names.

---------------------

The dot plot states that:

  • 2 students have 4 vowels in their first and last name.
  • 3 students have 5 vowels.
  • 8 students have 6 vowels.
  • 9 students have 7 vowels.

Then:

  • Total of 2 + 3 + 8 + 9 = 22 students.
  • 3 + 8 + 9 = 20 have or more vowels.

p = \frac{20}{22} \times 100\% = 90.91\%

90.91% of the students have 5 or more vowels in their first and last  names.

A similar problem is given at brainly.com/question/14354536

5 0
3 years ago
What is the probability of flipping two coins at the same time and getting heads on both coins?
Romashka-Z-Leto [24]
According to me the probability is 1/4, because there are 4 possible outcomes when two coins are flipped - TT, TH, HT, HH. 

<span>Also, would it matter if the coins are flipped one after other rather than together</span>
5 0
3 years ago
Read 2 more answers
Number 8 pleaseee !!!
MissTica
-6/7 < -6.7


i hope this helps

7 0
3 years ago
Read 2 more answers
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