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ivolga24 [154]
3 years ago
12

I need some help please and thank you ​

Mathematics
1 answer:
lukranit [14]3 years ago
3 0
The answer is “ A.) $3.50 “
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HELP!!
murzikaleks [220]

Answer:

Explicit:

a(n) = (5^n)/5

Recursive:

a(n) = 5 × a(n-1)

Step-by-step explanation:

1, 5, 25, 125...

1, 1×5 = 5, 5×5 = 25, 25×5 = 125..

It is a Geometric sequence with:

First term: 1

Common ratio: 5

Nth term of a Geometric sequence is:

a(n) = a(1) × r^(n-1),

Where a(1) is the first term and r is the common ratio.

Therefore,

a(n) = 1 × 5^(n-1)

a(n) = 5^n × 5^-1

a(n) = (5^n)/5

Recursive:

a(n) = 5 × a(n-1)

4 0
3 years ago
Read 2 more answers
Helpppppp meeeee pleaseeeeeeee
zlopas [31]

Answer:

The answer is 7/9

Step-by-step explanation:

Had this on my quiz one time

4 0
3 years ago
Read 2 more answers
Due Today! A student used the slope-intercept form to write the equation of a line that has a slope of -2 and passes through the
IceJOKER [234]

Answer:

Answer d (student needed to add the b value)

Step-by-step explanation:

I got it right

4 0
4 years ago
If ∫−1−4f(x)dx=0 and ∫31g(x)dx=3, what is the value of ∫∫Df(x)g(y)dA where D is the square: −4≤x≤−1, 1≤y≤3?
Lana71 [14]

Answer:

0

Step-by-step explanation:

From your problem, we have to extract the information that are important from the first two intregrals so we can solve the double integral.

\int\limits^{-1}_{-4} {f(x)} \, dx = 0

We also have that:

\int\limits^{3}_{1} {g(x)} \, dx = 3

---------------------------------

With this, now we can solve the double integral.

Since the limits of integration are constant, i can use dA both as dydx or dxdy. I am going to use dydx.

So the double integral will be:

\int \limits^{-1}_{-4} \int \limits^{3}_{1} {g(y)} {f(x)} dy dx\

We solve a double integral from the inside to the outside, so the first integral we solve is:

\int \limits^{3}_{1} \y g(y) \x f(x) dy

f is a function of x and we are integrating dy, so this means that f is a constant. Our integral now is this:

\x f(x) \int \limits^{3}_{1} \y g(y) dy

From above, we have that

\int \limits^{3}_{1} \x g(x) dx = 3

So,

\int \limits^{3}_{1} \y g(y) dy = 3

Now we have to solve the outside integral:

3\int\limits^{-1}_{-4} {f(x)} \, dx

We know that

\int\limits^{-1}_{-4} {f(x)} \, dx = 0

So the double integral will be 0

3 0
3 years ago
The first terms of a geometric sequence are 0.778,-2.33,7,-21, and 63. What is the 6th term?
aliya0001 [1]

Answer:

-189

Step-by-step explanation:

If you continue the pattern by multiplying the term by -3, you will eventually get -189 as the 6th term

3 0
4 years ago
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