Complete the statement. Round to the nearest hundredth if necessary. 6 cm ≈ in.
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The probability that a random sample of 12 second grade students results in a mean reading rate of more than 95 words per minute is 0.4582.
Given that the population mean, = 90 wpm
The standard deviation of the population , = 10
Sample size, n = 12
Sample mean, = 95
The reading rate of students follows the normal distribution.
Let z =
=
= 1.732
Probability that the mean reading exceeds 95 wpm = P( >95)
= P(z>1.732)
= 1- P(z<1.732)
= 0.4582
[The value 0.4582 found from the area under the normal curve using tables].
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