3 years ago

What type of equations could have extraneous solutions?

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

4 0

Answer:

Step-by-step explanation:

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At the base of a pyramid, a surveyor determines that the angle of elevation to the top is °. At a point meters from the base, th

riadik2000 [5.3K]

Answer:

$\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}$

Step-by-step explanation:

Incomplete question:

$\angle CBD = 53^\circ$

$\angle CAB = 35^\circ$

$AB = 75$

See attachment for complete question

Required

Determine the equation to find x

First, is to complete the angles of the triangle (ABC and ACB)

$\angle ABC + \angle CBD = 180$ --- angle on a straight line

$\angle ABC + 53= 180$

Collect like terms

$\angle ABC =- 53+ 180$

$\angle ABC =127^\circ$

$\angle ABC + \angle ACB + \angle CAB = 180$ --- angles in a triangle

$\angle ACB + 127 + 35 = 180$

Collect like terms

$\angle ACB =- 127 - 35 + 180$

$\angle ACB =18$

Apply sine rule

$\frac{\sin A}{a} = \frac{\sin B}{b}$

In this case:

$\frac{\sin ACB}{AB} = \frac{\sin CAB}{x}$

This gives:

$\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}$

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