All categories

3 years ago

May you please help me figure out every angle?

Mathematics

1 answer:

djyliett [7]3 years ago

8 0

Answer:

<D = 82°

<E = 49°

<F = 49°

Step-by-step explanation:

This is an isosceles triangle because two of the sides are the same length which means the 2 bottom angles are the exact same which means we can set them equal to each other to solve for it.

You might be interested in

What is 0.675 in its simplest form?

Musya8 [376]

27 over 40 (as a fraction)

WORK:
.675 is 675 over 1000
5 goes into both of those so
675/5=135 1000/5=200
135/5=27
200/5=40

3 0

3 years ago

Emmanuel bought 28 lb of potting soil this week. This amount is 4 lb more than twice the amount of potting soil he bought last w

hammer [34]

He bought 60 pounds last week and p stands for 60

5 0

3 years ago

Alguem me ajuda<br>por favor

andre [41]

Answer:

sorry I'm confused boy sorryy

6 0

3 years ago

Find the equation of this line.<br> Acellus

aalyn [17]

Answer:

Step-by-step explanation:

two points on the line are (-3,-2) and (5,4)

slope=(4+2)/(5+3)=6/8=3/4

eq. of line is

y+2=3/4 (x+3)

4y+8=3x+9

4y=3x+1

y=3/4 x+1/4

8 0

2 years ago

Find the area under the curve y = 27/x3 from x = 1 to x = t. Evaluate the area under this curve for t = 10, t = 100, and t = 100

Darina [25.2K]

Answer:

Step-by-step explanation:

given is a function as

$y=\frac{27}{x^3}$

We are to find the area form x=1 to x=t

The curve from x=1 lies in the I quadratnt.

So area above x axis is to be calculated

Area = $\int\limits^t_1 {\frac{27}{x^3} } \, dx \\=\frac{-27}{2x^2} \\= \frac{-27}{2t^2}-\frac{-27}{2}\\=\frac{27}{2}(1-\frac{1}{t^2} )$

a) When t =10,

area = $\frac{27}{2} (1-\frac{1}{10^2} )\\= 13.365$

b) t=100

area = $\frac{27}{2} (1-\frac{1}{100^2} )\\= 13.49865$

c) t=10000

area = $\frac{27}{2} (1-\frac{1}{10000^2} )\\= 13.5$

6 0

3 years ago

May you please help me figure out every angle?​

May you please help me figure out every angle?