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Anna71 [15]
3 years ago
15

Which proof proves this? Legit need help!

Mathematics
1 answer:
Ahat [919]3 years ago
4 0

Answer:

Angle B = Angle D

Step-by-step explanation:

If it says it's a reflection, then as long as it's not stretched or shrunk, both sides will be equal across the line of symmetry

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You go to the quad on a windy day to fly a kite. You have released 40 feet of string. The string makes an angle of 36° with the
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I NEED THE ANSWERS QUICK!!! PLEASE TELL ME ILL GIVE BRAINLIEST!!!!!!!!!!!!
Ulleksa [173]

Answer:

(3,-8) (2,-10)

Step-by-step explanation:

Graph and see where the points are, if they are in the solution, they are correct.

Please mark me brainlist and solve the question I just asked.

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3 years ago
Help math! Explain! Brainliest stars and hearts if correct!
zhenek [66]
Y=2
the x axis value didn’t change , only the y value did
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7 0
3 years ago
The midpoint of AB is M(-2, 1). If the coordinates of A are (-3,-5),
mrs_skeptik [129]

Answer:

B= (-1, 7)

Step-by-step explanation:

Midpoint formula is X1 plus X2, then divided by 2. So, because the midpoint is given you work backwards. So for the x value do (-3 + x) divided by 2 equals -2 and solve for x and you do the same thing for the Y value

8 0
3 years ago
Julian’s friend James also has a tank in the shape of a triangular prism. The dimensions of James’ tank are each exactly 2 3/4 t
malfutka [58]

The approximate area of the triangular base of James’ tank is 3025 in²

To find the approximate area of the triangular base of James' tank, we need to know what scale is.

<h3>What is scale?</h3>

A scale is the ratio of two dimension. It is given by scale = New dimension/old dimension

Given that the dimensions of James’ tank are each exactly 2 3/4 times the dimensions of Julian’s tank.

The scale of the area of James' tank to the area of triangular base of Julian's tank is S = (2³/₄)²

= (11/4)²

= 121/16

Let

  • A = area of triangular base of James' tank,
  • A' = area of triangular base of Julian's tank = 400 in²

So, scale, S = A/A'

<h3>The approximate area of the triangular base of James’ tank</h3>

So, making A subject of the formula, we have

A = SA'

A = 121/16 × 400 in²

A = 121 × 25 in²

A = 3025 in²

So, the approximate area of the triangular base of James’ tank is 3025 in²

Learn more about area of triangle here:

brainly.com/question/27436493

#SPJ1

5 0
3 years ago
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