6.665 grams of the 13 grams remain after 8 hours.
<h3>How much of a 13 gram sample of iron-52 would remain after 8 hours?</h3>
The decay equation for the 13 grams of iron-52 is:
Where N is the amount of iron-52, and t is the time in years.
Where we used the fact that the half-life is exactly 8.3 hours.
Now, the amount that is left is given by N(8h), so we just need to replace the variable t by by 8 hours, so we get:
So 6.665 grams of the 13 grams remain after 8 hours.
If you want to learn more about half-life:
brainly.com/question/11152793
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Multiply -3/11 and -2/15 straight across
-3(-2) = 6
11(15) = 165
6/165 is your product, or 0.036 (rounded)
hope this helps
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40x - 24 - 33x - 77 = 102
40x - 33x = 102 + 24 + 77
7x = 203
x = 29
For this case we have the following system of equations:
From the first equation we clear "x":
We substitute in the second equation:
We apply distributive property:
We add similar terms:
We add 65 to both sides:
We divide between 22 on both sides:
We look for the value of the variable "x":
Thus, the solution of the system is:
ANswer:
