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3 years ago

Example : C For Cheeseburger , S for small and etc

Mathematics

2 answers:

Nookie1986 [14]3 years ago

8 0

Answer:

3+2+2-1+2=8

Step-by-step explanation:

Hope this helps!

alexandr1967 [171]3 years ago

8 0

3+2+2+-1+2=8

3+2 = 5
5+2=7
7-1=6
6+2=8
answer= 8

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2. A chemist has a 25% and a 50% acid solution. How

AnnZ [28]

Answer:

x is mL of 25% acid and y is mL of 50% acid

We set up 2 equations:

A) x + y = 250

B) .25 x + .50y = .35 * 250 which equals

B) .25x + .50y = 87.50 Multiplying A) by -.5

A) -.5x -.5y = -125 adding the equations we get

-.25x = -37.50

x = 150 mL

y = 100 mL

Source: http://www.1728.org/mixture.htm

Step-by-step explanation:

7 0

3 years ago

Help me please right away

umka2103 [35]

${t}^{2} = \frac{4b {x}^{2} }{k} \\ k {t}^{2} = 4b {x}^{2} \\ \frac{k {t}^{2} }{4b} = {x}^{2} \\ x = \sqrt{ \frac{k {t}^{2} }{4b} } = 0.5t \sqrt{ \frac{k}{b} }$

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3 years ago

Mrs. DeLouise bought scarf material that was 9 feet long. She cut the scarf material into pieces that were each 1/3 foot long to

Aloiza [94]

Answer:

3 Scarfs

Step-by-step explanation:

Hope that helped .

3 0

3 years ago

Read 2 more answers

The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find

9966 [12]

Answer:

The particular integral of given differential equation

$y_{p} = \frac{1}{4} ( x - (\frac{-5}{4} ) (1))$

General solution of given differential equation

$y = y_{c} + y_{p}$

$Y (x) = C_{1} e^{x} + C_{2} e^{4x} + \frac{1}{4} ( x + (\frac{5}{4} ))$

Step-by-step explanation:

Step(i):-

Given Differential equation y'' − 5 y' + 4 y = x

Given equation in operator form

D²y - 5 Dy + 4 y = x

⇒ ( D² - 5 D + 4 ) y =x

⇒ f(D) y = Q

where f(D) = D² - 5 D + 4 and Q(x) = x

The auxiliary equation f(m) =0

m²-5 m + 4 =0

m² - 4 m - m + 4 =0

m ( m -4 ) -1 ( m-4) =0

(m - 1) =0 and ( m-4) =0

m = 1 and m =4

The complementary function

$Y_{c} = C_{1} e^{x} + C_{2} e^{4x}$

Step(ii):-

particular integral

Particular integral

$y_{p} = \frac{1}{f(D)} Q(x) = \frac{1}{D^{2} - 5 D + 4} X$

taking common '4'

$= \frac{1}{4(1 + (\frac{D^{2} - 5 D}{4} ))} X$

$=\frac{1}{4} (1 + (\frac{D^{2} -5D}{4})^{-1} )} X$

applying binomial expression

( 1 + x )⁻¹ = 1 - x + x² - x³ +.....

$=\frac{1}{4} (1 - (\frac{D^{2} -5D}{4}) +((\frac{D^{2} -5D}{4})^{2} -...} )X$

Now simplifying and we will use notation D = $\frac{dy}{dx}$

$=\frac{1}{4} (x - (\frac{D^{2} -5D}{4})x +((\frac{D^{2} -5D}{4})^{2}(x) -...}$

Higher degree terms are neglected

$=\frac{1}{4} (x - (\frac{ -5 D}{4}) x)$

The particular integral of given differential equation

$y_{p} = \frac{1}{4} ( x - (\frac{-5}{4} ) (1))$

Final answer:-

General solution of given differential equation

$y = y_{c} + y_{p}$

$Y (x) = C_{1} e^{x} + C_{2} e^{4x} + \frac{1}{4} ( x + (\frac{5}{4} ))$

4 0

3 years ago

What is the center and radius of circle with the equation? x^2+ y^2+12x-8y+39 = 0

myrzilka [38]

Answer:

Center is (-6,4) and the radius is √13

Step-by-step explanation:

4 0

3 years ago