Answer:
a. b. d.
Step-by-step explanation:
Answer:
i think the answer is option c
The total number of handshakes was 234.
- The first man shook hands with 12 other men.
- The second man shakes hands with 11 other men, as he had already shaken hands with the first man.
- Like-wise, the last man does not need to shake hands again as every man has already shaken hands with him in their respective turns.
- The number of handshakes among men is 0 + 1 + 2 + … + 12.
- The sum of "n" natural numbers = (n)(n+1)/2
- The number of handshakes among men is 12(13)/2.
- The number of handshakes among men is 78.
- Each man shakes hands with every woman except his spouse.
- Each man shakes hands with 12 other women.
- The number of handshakes between men and women is 13*12.
- The number of handshakes between men and women is 156.
- The total number of handshakes is 78 + 156.
- The total number of handshakes is 234.
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Every time you see r, replace it with -3. Every time you see s, replace it with 5. You are working wth exponents, which means that the little number next to the big number (exponent) is how many times you multiply the big number by itself.
For example, 5^3=5x5x5=125 (isn't one of the problems you are trying to solve)
If the expodent is negative, then you divide. S<span>so if it's like 5^-3, you do 1 ÷ 5 ÷ 5 ÷ 5 = 0.008 </span>
Hope this helps! :)
Answer:
8.3%
Step-by-step explanation:
In a simple way, we know that both are independent events, therefore, in the case of the dice it has 6 faces, therefore the probability of 3 coming out is 1/6 and in the case of the coin it only has two options, which means that the probability is 1/2.
Now the final probability is the multiplication of these events, that is:
1/6 * 1/2 = 0.083
Which means that the probability of these two events happening is 8.3%
