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2 years ago

HELP IM TAKING THE TEST IN CLASSSS

Mathematics

1 answer:

Flura [38]2 years ago

5 0

Answer: the 1 one

Step-by-step explanation:

You might be interested in

Please help! I'll give Brainleist if someone gets this right.

enot [183]

Answer:

Hope this helps!

Step-by-step explanation:

Brianna did it right, and 552 divided by 23 is 24!

Please give brainiest if you think my answer is good :)

7 0

3 years ago

Read 2 more answers

Evaluate using integration by parts

PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

$I(n)=\displaystyle\int x^ne^x\,\mathrm dx$

One round of IBP, setting

$u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx$

$\mathrm dv=e^x\,\mathrm dx\implies v=e^x$

gives

$\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx$

$I(n)=x^ne^x-nI(n-1)$

This is called a power-reduction formula. We could try solving for $I(n)$ explicitly, but no need. $n=5$ is small enough to just expand $I(5)$ as much as we need to.

$I(5)=x^5e^x-5I(4)$

$I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)$

$I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)$

$I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)$

$I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))$

Finally,

$I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C$

so we end up with

$I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C$

$I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C$

and the antiderivative is

$\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C$

8 0

3 years ago

Dose anyone have the answer to this question

Anuta_ua [19.1K]

Answer: (A) SAS (B) No (C) SSS (D) No

<u>Step-by-step explanation:</u>

A) ET ≅ MT, ∠T ≅ ∠T, TA ≅ TA ⇒ Side-Angle-Side

B) top and base are congruent, diagonal is congruent to itself, but there is no way to prove that two angles are congruent without knowing if either of the sides are parallel.

C) JU ≅ JE, UN ≅ EN, JN ≅ JN ⇒ Side-Side-Side

D) angle-angle-angle only proves similarity, not congruency

7 0

3 years ago

It is 2.3 km from Salma's house to the nearest mailbox. How far is it in meters?

Ivenika [448]

Answer:

2.3km in meters is 2300 Meters

Step-by-step explanation:

Multiply the length value by 1000

7 0

3 years ago

Gwen, Tristan, and Keith like to work out at the gym. They each have an app on their phone that estimates the calories they burn

aleksandrvk [35]

Answer:

Part A:

Gwen has already burned 100 calories when Tristan and Keith started, and he continues to burn 10 calories per minute. The equation for Gwen is

y = 100 + 10x

Part B:

Tristan is burning 125 calories every 10 minutes. His burning calories rate is 12.5 calories per minute. The equation for Tristan is

y = 12.5x

Part C:

Keith is burning 300 calories in 30 minutes. His rate per minute is 10 calories per minute. The equation for Keith is

y = 10x

Part D:

Just follow the instructions and do the thing for the app. You can then answer the questions it is very easy.

Part E:

Do the same for E after you do Part D.

Step-by-step explanation:

Hope it helps!

6 0

2 years ago

Read 2 more answers

HELP IM TAKING THE TEST IN CLASSSS​

HELP IM TAKING THE TEST IN CLASSSS