Answer:
The answer to your question is There were sold 166 adult tickets and 294
children tickets.
Step-by-step explanation:
Data
Total number of seats = 460
cost for adults = a = $52
cost for children = c = $26
Total cost = $16276
Process
1.- Write equations to solve this problem
a + c = 460 Equation l
52a + 26c = 16276 Equation ll
2.- Solve the system of equation by substitution.
-Solve equation l for a
a = 460 - c
-Substitute a in equation ll
52(460 - c) + 26c = 16276
-Expand
23920 - 52c + 26c = 16276
-Simplify
-26c = 16276 - 23920
-26c = -7644
c= -7644/-26
c = 294
3.- Find a
a = 460 - 294
a = 166
It would be 10 times greater im pretty sure.
By calculating monthly incom and debt the 2nd one
First computer takes x min. For 1 min it does 1/x part of work.
Second computer takes (x+24) min. For one min it does 1/(x+24) part of work.
Both computers for one min do (1/x+1/(x+24)) part of work.
At the same time, both computers for one min do 1/9 part of work.
I’m pretty sure the answer is C