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3 years ago

The senior classes at High School A and High School B planned separate trips to the local

Mathematics

1 answer:

goblinko [34]3 years ago

4 0

I’m not sure if I will

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Question<br> Francie rode her bike for 2.5<br> hours at 12 miles per hour. How far did she ride?

DochEvi [55]

Answer:

30 miles

Step-by-step explanation:

2.5 h

12 miles per hour

12x2.5=30

6 0

3 years ago

Can someone help me with this question I'll give brainliest answer to whoever helps.

guapka [62]

Answer: B) It represents the product of two irrational numbers and is equivalent to an irrational number.

Step-by-step explanation:

1. By a definition an irrational number cannot be written as a simple fraction.

2. Keeping this information on mind:

$\sqrt{3}=1.73$ (Cannot be written as a simple fraction. It is an irrational number).

$\sqrt{2}=1.41$ (Cannot be written as a simple fraction. It is an irrational number).

3. When you multiply this irrational number, you obtain:

$\sqrt{3}*\sqrt{2}=\sqrt{6}$

4. $\sqrt{6}=2.44$ is an irrational number.

5. Therefore, the answer is the option B,

7 0

3 years ago

Use induction to show that 12 + 22 + 32 + ... + n2 = n(n+1)(2n+1)/6, for all n > 1.

dlinn [17]

Answer with Step-by-step explanation:

Let $P(n)=1^2+2^2+3^2+.....+n^2=\frac{n(n+1)(2n+1)}{6}$

Substitute n=2

Then $P(2)=1+2^2=5$

$P(2)=\frac{2(2+1)(4+1)}{6}=5$

Hence, P(n) is true for n=2

Suppose that P(n) is true for n=k >1

$P(k)=1^2+2^2+3^2+...+k^2=\frac{k(k+1)(2k+1)}{6}$

Now, we shall prove that p(n) is true for n=k+1

$P(k+1)=1^2+2^2+3^2+...+k^2+(k+1)^2=\frac{(k+1)(k+2)(2k+3)}{6}$

LHS

$P(k+1)=1^2+2^2+3^2+.....+k^2+(k+1)^2$

Substitute the value of P(k)

$P(k+)=\frac{k(k+1)(2k+1)}{6}+(k+1)^2$

$P(k+1)=(k+1)(\frac{k(2k+1}{6})+k+1)$

$P(k+1)=(k+1)(\frac{2k^2+k+6k+6}{6})$

$P(k+1)=(k+1)(\frac{2k^2+7k+6}{6})$

$P(k+1)=(k+1)(\frac{2k^2+4k+3k+6}{6})$

$P(k+1)=\frac{(k+1)(k+2)(2k+3)}{6}$

LHS=RHS

Hence, P(n) is true for all n >1.

Hence, proved

4 0

3 years ago

What is the answer plz need help

Tamiku [17]

$\frac{11}{?10}$

4 0

3 years ago

How to graph y=12 and x=0?

Effectus [21]

Just look at the graph

7 0

3 years ago