1) Surface Area = 2(lw + lh + wh)
2(4*5+4*9+5*9) =202in^2
Surface Area=202in^2
Lateral Area= Perimeter of base * height
5+5=10 <--width+width
4+4=8 <---length + length
10+8=18 <--total perimeter
18 * 9=162in^2 <--multiplied the height +perimeter of base
Lateral Area=162in^2
2) Same concept as the previous one
Surface Area = 2(lw + lh + wh)
2(4*2+4*5+5*2) =76in^2
Surface Area= 76in^2
Lateral Area
Lateral Area= Perimeter of base * height
4+4=8
2+2=4
8+4=12
12 x 5=60
Lateral Area= 60in^2
The answer to your question is = 148.06
Answer:
4. 55 (or is that a 56 its a low res image srry)
5. PWA is vertical, nothing is corresponding
6. 8y
7. wap is vertical 9x-2 is corresponding
8. wap is supplementary uyi is corresponding
9. tad
10. rps
We know that AB and CD are parallel. This allows many assumptions.
From that we know that angle A and angle D are congruent.
That means that x + 8 = 2x - 22 and we can solve for x
x + 8 = 2x - 22
x + 30 = 2x
30 = x or x = 30
We know from the figure that angle B is x or now that we solved for x is 30 degrees. Also, we know that both angle A and angle D are 38 degrees. Now we can solve for the vertical angle E which has a measure of y degrees. A triangle has the sum of its angles equal to 180 degrees.
We can set up an equation like this 30 + 38 + y = 180
30 + 38 + y = 180
68 + y = 180
y = 112 degrees
That is how you would solve this problem
