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OLEGan [10]
3 years ago
5

If 2 pounds of halibut cost $16, what is the unit rate for 1 pound?

Mathematics
2 answers:
Blizzard [7]3 years ago
5 0

Answer:

8?

Step-by-step explanation:

adoni [48]3 years ago
3 0

Answer: $8

Step-by-step explanation: 2:16 = 1:8

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Can someone smart help me with this plz:)
insens350 [35]

Answer:

Step-by-step explanation:

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6p + 6p + 3 p = 180

15p = 180

p = 180/15

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Angles are:

6p = 6*12 = 72°

3p = 3*12 = 36°

Angles are: 72°, 72° , 36°

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weeeeeb [17]

Answer:

x = -14

Step-by-step explanation:

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Round 38.725 to the nearest tenth​
shtirl [24]

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38.7

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2 years ago
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Alec is doing a test of 50 questions. He gets 2 marks for every question that is correct, but loses 1 mark for every question th
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Alec got 33 and a half questions correctly because he got one mark on the 34th Question

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(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
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