The answer is:
There are 595 calories in a banana split To find this we first need to set up our equation:
, where x= calories in a banana split
----------------Add 5 to both sides
595=x-------------------Multiply 7 to both sides to get rid of the fraction
So, there are 595 calories in a banana split
Hope this helps! :)
Answer:
percent change = 27.5 % decrease
Step-by-step explanation:
percent change = (original - new)/original
percent change = (160-116)/160
percent change = 44/160
percent change =.275
change from a decimal
percent change = 27.5 % decrease
Compute the gradient of 
.
Set this equal to the zero vector and solve for the critical points.
The last case has no real solution, so we can ignore it.
Now,
so we have two critical points (0, 0) and (2, 2).
Compute the Hessian matrix (i.e. Jacobian of the gradient).
Check the sign of the determinant of the Hessian at each of the critical points.
which indicates a saddle point at (0, 0);
We also have 
, which together indicate a local minimum at (2, 2).
let f(r)=sin^3r/cos^3r
so f(-r)= (sin(-r)/cos(-r))^3
=(-sinr/cosr)^3
=-f(r)
so it is odd function
Use same-length line segments to solve for x and y.
... PS = SR
... 4x +4 = 7x -17
... 21 = 3x . . . . . . . . . add 17-4x
... 7 = x . . . . . . . . . . . divide by 3
... PS = SR = 4·7+4 = 32
... PQ = QR
... 5y -31 = 2y +5
... 3y = 36 . . . . . . . . . add 31-2y
... y = 12 . . . . . . . . . . . divide by 3
... PQ = QR = 2·12 +5 = 29
... PT = TR = 6·7-2·12 = 18
