No because In the relation , y is a function of x, because for each input x (1, 2, 3, or 0), there is only one output y. x is not a function of y,
<span><span>Make it a solid line for y≤ or y≥, and a dashed line for y< or y>
</span><span>Shade above the line for a "greater than" (y> or y≥)
or below the line for a "less than" (y< or y≤).
So, the answer is A) </span></span><span>x + 4y ≥ −4
</span><span>x + 4y ≥ −4
4y </span>≥ -x - 4
y ≥ -x/4 - 1
Answer:
Where is the question?
Step-by-step explanation:
I can't answer without the question sorry... but please give me thanks I just started brainly and a brainliest would be amazing. Thank you guys in advance.
There are 2 possibilities for where A can be: one where C is 30° (and A is 60°) and another where C is 60° (and A is 30°). Since it's not specified, we can find both.
30°:
drawing the triangle on a graph, you can see that point C is 4 units above point B, so we know that one side of the triangle is 4. Once we find the other "leg" of the triangle (the one that's parallel to the x-axis), we can just add that value to B to find the x coordinate of A.
If angle C is 30°, using the side ratios of a 30-60-90 triangle, that side is "a√3", and the side we're looking for is a. So, to find a, we just divide 4 by √3. In that case, point A is 4/(√3) units to the right of -2√3. We can rationalize 4/(√3) like this:
(4√3)/3
and then add that to 2√3:
(4√3)/3 + -2√3
(4√3)/3 + (-6√3)/3 = (-2√3)/3
We know that the x-coordinate of A is (-2√3)/3, and the y-coordinate is -1 because B is a right angle and we're just moving horizontally. So, if C is 30° and A is 60°, point A is at ((-2√3)/3, -1).
60°:
in this case, the leg we know is "a" and the leg we're looking for is "a√3". So, we can multiply 4 by √3 to get the distance from B:
4 x √3 = 4√3
4√3 + -2√3 = 2√3
So the x-coordinate of A here is 2√3, and the y-coordinate is still -1: (2√3, -1).
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Answer:
x=5
Step-by-step explanation:
x is the length of the line segment from the center to the boderline of circle. So x=5
