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3 years ago

Raphael is timing how fast he can do a series of 5

Mathematics

1 answer:

Nana76 [90]3 years ago

4 0

Answer:

Time left for each question is less than 5.5 minutes

Step-by-step explanation:

Given that:

Raphael is trying to solve 5 math questions in less than 20 minutes.

3 questions have been completed which have taken 3 minutes each.

To find:

How much time is left with Raphael for each question so as to reach his goal.

Solution:

First of all, let us find the time that has been already consumed by Raphael in solving the 3 questions.

3 $\times$ 3 = 9 minutes

Time left = Total Time - Time already consumed

Time left = 20 - 9 = 11 minutes

Number of questions to be solved = Total questions - Questions solved

Number of questions to be solved = 5 - 3 = 2

Average time left for each question = Time left divided by Number of questions to be solved

Average time left for each question = 11 $\div$ 2 = 5.5 minutes

Therefore, time left for each question is less than 5.5 minutes.

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Https://allmylinks.com/zeoathiras<br><br> I’m bored. Owo

Savatey [412]

Answer:

Yeah same here

Step-by-step explanation:

8 0

2 years ago

Weight of a rock: In a geology course, students are learning to use a balance scale to accurately weigh rocks. One student plans

statuscvo [17]

Answer:

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

Step-by-step explanation:

What is Confidence Interval?

The confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.

The confidence interval is given by

$CI = \bar{x} + t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\$

Where $\bar{x}$ is the mean weight $\sigma$ is the standard deviation $t_{\alpha/2}$ is the critical value from t-table and n is the sample size.

The term $t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } )$ is known as margin of error.

As the sample size is decreased the corresponding margin of error increases which results in wider confidence interval which means smaller precision.

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

We can say with 95% confidence that the true mean weight of the rock is within the interval of (25.2, 29.1).

7 0

3 years ago

10 2.5 16 4 ? 7.5 48 12 Which statement explains how to find the number of minutes it takes to bike 7.5 miles? Find the ratio of

svet-max [94.6K]

Answer:

Find the ratio of minutes to miles, 4:1. Multiply 7.5 by 4.

Step-by-step explanation:

Given

Minutes: 10 || 16 || ? || 48

-----Miles: 2.5 || 4 || 7.5 || 12

Required

Which statements solve for the missing value?

First, we need to calculate the ratio of minutes to mile

$Ratio = \frac{Minutes}{Mile}$

When minutes = 16; mile = 4

So, we have:

$Ratio = \frac{16}{4}$

$Ratio = 4$

Next, we multiply the ratio by 7.5

$Minutes = Ratio * 7.5$

$Minutes =4 * 7.5$

$Minutes = 30$

<em>Hence, option B answers the question.</em>

7 0

3 years ago

Approximate the real number solution(s) to the polynomial function f(x) = x3 + 2x2 − 5x − 6.

nadya68 [22]

F(1) = (1)^3 + 2(1)^2 - 5(1) - 6 = 1 + 2 - 5 - 6 = -8; x = 1 is not a solution to the polynomial.
f(-1) = (-1)^3 + 2(-1)^2 - 5(-1) - 6 = -1 + 2 + 5 - 6 = 0; x = -1 is a solution to polynomial.
From the options, a or c has x = -1, both has x = , so lets check for x = 3
f(3) = (3)^3 + 2(3)^2 - 5(3) - 6 = 27 + 18 - 15 - 6 = 24; x = 3 is not a solution to the polynomial.
Therefore the solutions to the polynomial are x = -3, x = -1, x = 2

6 0

3 years ago

How does a change in the value of h effect the axis of symmetry of the graph ? How does the value of k change the axis of symmet

Ber [7]

The value of h is exactly the axis of symmetry. So when h changes, it completely changes the line of symmetry. This is because the vertex is (h, k) and the x value of the vertex is always equal to the line of symmetry in a quadratic.

Changing the k value does nothing to the line of symmetry. This is because it is just moving the graph up and down, which doesn't change the symmetry of a parabola.

5 0

3 years ago