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Lisa [10]
3 years ago
8

Raphael is timing how fast he can do a series of 5

Mathematics
1 answer:
Nana76 [90]3 years ago
4 0

Answer:

Time left for each question is less than 5.5 minutes

Step-by-step explanation:

Given that:

Raphael is trying to solve 5 math questions in less than 20 minutes.

3 questions have been completed which have taken 3 minutes each.

To find:

How much time is left with Raphael for each question so as to reach his goal.

Solution:

First of all, let us find the time that has been already consumed by Raphael in solving the 3 questions.

3 \times 3 = 9 minutes

Time left = Total Time - Time already consumed

Time left = 20 - 9 = 11 minutes

Number of questions to be solved = Total questions - Questions solved

Number of questions to be solved = 5 - 3 = 2

Average time left for each question = Time left divided by Number of questions to be solved

Average time left for each question = 11 \div 2 = 5.5 minutes

Therefore, time left for each question is less than 5.5 minutes.

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Answer:

2.5477 feet

Step-by-step explanation:

Refer the image attached to understand my solution.

BC = height of lamppost.

DE = Julia

AD = shadow of Julia

BD = 2 feet.      AD = 5 feet

BA = BD + AD

       = 2 + 5 = 7 feet

In ΔABC

tan 20° = \frac{BC}{BA}  = \frac{BC}{7}

BC = 7 * tan 20°

BC = 2.5477 feet

SO the height of lamppost = 2.5477 feet

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Answer:

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