Question

Find the volume of the solid generated by revolving the region bounded by the x-axis, the curve y = 3x^4 , and the lines x = 1 and x = -1 about the x-axis.

Answer 1

Answer:

Let's define A as the area given by the integral:

$\int\limits^1_{-1} {3x^4} \, dx$

Which is the area between the curve y = 3*x^4 and the x-axis between x = -1 and x = 1

To find the volume of a revolution around the x-axis, we need to multiply the area by 2*pi (a complete revolution)

where pi = 3.14

First, let's solve the integral:

$\int\limits^1_{-1} {3x^4} \, dx = \frac{3}{5}(1^5 - (-1)^5) = \frac{3*2}{5} = \frac{6}{5}$

Then the volume of the solid is just:

V = (6/5)*2*3.14 = 7.536