Howard is laying an oak wooden floor in his house. The measurements of the floor are 14.5 feet by 40 feet. The wood is packaged
1 answer:
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Slope-intercept form of a line is y=mx+b where m= slope and b=y-intercept.
First step is to compare this line with the given line y=5x+2 to get the value of m.
After comparing we will get m=5.
Now slope of all parallel lines are equal which means if slope of this line is 5 then slope of the line which is parallel to this line will also be 5.
Point- slope form of a line is:
Given the line passes through (-6,-1). So, plug in x1=-6, y1=-1 and m=5 in the above equation. So,
y-(-1)=5(x-(-6))
y+1=5(x+6)
y+1=5x+30
y=5x+30-1
y=5x+29.
For convenience sake, I will let
First, we evaluate the function at the endpoints of the interval.
Then, we need to find the critical points.
We can start by taking the derivative using the power rule.
Setting this equal to 0,
Since , we can divide both sides by
.
So, the absolute minimum is and the absolute minima are
Answer:
The scale factor is (√10) / (4)
Explanation:
The complete question as well as the rule for the distance between two points are shown in the attached image.
To get the scale factor, we will follow these steps:
1- Length of AB:
AB = √(5-9)²+(-4-4)²
AB = √80
AB = 4√5 units
2- Length of A'B':
A'B' = √(5-6)²+(-4-3)²
A'B' = √50
A'B' = 5√2
3- getting the scale factor:
A'B' = k AB where k is the scale factor
5√2 = k * 4√5
k = (√10) / (4)
Hope this helps :)
The scale factor is (√10) / (4)
Explanation:
The complete question as well as the rule for the distance between two points are shown in the attached image.
To get the scale factor, we will follow these steps:
1- Length of AB:
AB = √(5-9)²+(-4-4)²
AB = √80
AB = 4√5 units
2- Length of A'B':
A'B' = √(5-6)²+(-4-3)²
A'B' = √50
A'B' = 5√2
3- getting the scale factor:
A'B' = k AB where k is the scale factor
5√2 = k * 4√5
k = (√10) / (4)
Hope this helps :)