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kipiarov [429]
3 years ago
9

Please help quickly!!!!!!!!!!The area of the regular pentagon is 6.9 cm2. What is the perimeter? 2 cm 5 cm 10 cm 20 cm

Mathematics
2 answers:
pishuonlain [190]3 years ago
7 0
10
random words to fill up 20 character minimum for answering questions :P
kirill [66]3 years ago
7 0

Answer:

Option C is correct.

The perimeter of the regular pentagon is, 10 cm

Step-by-step explanation:

The formula for the area of n-sided regular polygon is given by;

A = \frac{s^2 \times n}{4 \times \tan(\frac{180}{n})}  ......[1]; where s is the length of the side and n is the number of side .

Given: Area of regular pentagon is 6.9 square cm.

Here, n =5

to find s;

Substitute the value of A and n in equation [1];

6.9 =\frac{s^2 \times 5}{4 \times \tan(\frac{180}{5})}

or

6.9 = \frac{s^2 \times 5}{4 \times \tan(36)}

or

6.9 \times 4 \times \tan(36)= s^2 \times 5

s^2 =\frac{6.9 \times 4 \times \tan(36)}{5}

Taking both side square root, we have;

s=\sqrt{\frac{6.9 \times 4 \times \tan(36)}{5}}

Simplify:

s = 2.00263 cm

or

s ≈ 2.00 cm

Therefore, the side of the length of regular pentagon is, s≈ 2.00 cm

Now, to find the perimeter of regular pentagon;

Use the formula:

Perimeter of regular pentagon(P) = 5 \times s where s is the side.

Substitute the value of s≈ 2.00 cm.

P = 5 \times 2.00 = 10 cm

therefore, the perimeter of the regular pentagon is; 10 cm

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AlladinOne [14]

Answer:

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Step-by-step explanation:

In a quadratic equation in the Standard form

ax^2+bx+c=0

You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero: a\neq0).

You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:

-2x^2+4x-3=0

Therefore, you can identify that the values of "a", "b" and "c" are the following:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
If ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by what criterion?
Alborosie

No, not possible to tell that the the two triangles, ΔBAC and ΔCED

are similar ⇒ answer D

Step-by-step explanation:

Let us revise the cases of similarity

1. AAA similarity : two triangles are similar if all three angles in the first

  triangle equal the corresponding angle in the second triangle  

2. AA similarity : If two angles of one triangle are equal to the

   corresponding angles of the other triangle, then the two triangles  

   are similar.

3. SSS similarity : If the corresponding sides of the two triangles are

   proportional, then the two triangles are similar.

4. SAS similarity : In two triangles, if two sets of corresponding sides  

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In the two triangles BAC and CED

∵ m∠BAC = 17°

∵ m∠CED = 17°

∴ m∠BAC = m∠CED

But we need another pair of angles to prove that the two triangles are

similar by AA similarity criterion

<em>OR </em>

The lengths of sides BA , CA and CE , DE to show that

\frac{BA}{CE}=\frac{CA}{DE} = constant ratio and prove that the

two triangles are similar by SAS similarity criterion

So it is not possible to prove that the two triangles are similar

No, not possible to tell that the the two triangles, ΔBAC and ΔCED

are similar

Learn more:

You can learn more about triangles in brainly.com/question/4354581

#LearnwithBrainly

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