Which is equivalent to 4(x + 5) 4x + 9 4x + 20 4x + 5

Find the surface area of this rectangular prism. Be sure to include the correct unit in your answer.

nlexa [21]

Answer:

190 ft^2

Step-by-step explanation:

So first we need to find which equation we're using and since it's a rectangular prism we're going to use:

2Lw + 2wh + 2Lh

Now what we need to do is plug in the values

2*9*2 + 2*2*7 + 2*9*7

Now just multiply everything and then add it together.

36 + 28 + 126

Once you add everything together you get:

190

The question says to include the correct unit. It says that its feet, but we need to know if its feet squared (^2) or cubed (^3)

If it were area of the whole object, it would be cubed because it is all the area that the object takes up but since it's just the area of the surface it's going to be squared. Therefore, the answer is:

190 ft^2

4 0

3 years ago

In which of the number lines does the plotted point represent a number greater than -1 1/2? Check all that apply.

Nikitich [7]

Hi!

The first number line is equals to $-1\frac{1}{2}$

The second number line is equals to $\frac{-1}{2}$

The third number line is equals to $-2\frac{1}{2}$

The fourth number line is equals to 2

The fifth number line is equals to 0

The sixth number line is $-2\frac{3}{4}$

The answer is; second, fourth and fifth number lines.

I hope, I could help.

Wish Good Lessons! ^-^

6 0

3 years ago

Read 2 more answers

Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

$\qquad \sf \dashrightarrow \: h {}^{} = {10}$

Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0

2 years ago

For what value of a do the lines 5x–2y=3 and x+y=a intersect at a point on the y-axis?

inna [77]

Answer:

a = -3/2

Step-by-step explanation:

You can set x=0 and solve for y to find the y-intercept in each case.

first equation: y-intercept = -3/2

second equation: y-intercept = a

To make these equal, we must have ...

a = -3/2

5 0

3 years ago

Please answer this question!!

Aloiza [94]

To find the surface area of the rectangular prism you do.

2(lw + lh + wh).

2((26*18) + (26*8) + (18*8))

2(468 + 208 + 144)

2* 820

the answer is 1640cm^2

8 0

3 years ago