The cylinder is a clue to use cylindrical coordinates. Taking

and

, we then are forced to use

. So the parameterization of the intersection of the plane and cylinder is

To get the surface, we can introduce a second parameter

that "contracts" the elliptical intersection to a point. The simplest way to do this is to use

with

and

.
ANSWER
D.

EXPLANATION
The standard equation of the hyperbola is

We multiply through by 36 to obtain:

We now expand to get,

Expand :

To get the general form, we equate everything to zero to get,

The correct choice is D.
Answer:
The answer is: 181.5 square centimeters.
Step-by-step explanation:
The cube has six faces, and each face is a square with sides of length 5.5, so the area of one of this faces is
, adding the six faces, we get the answer: 