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3 years ago

10

Adding cheese to a McDonald's Quarter Pounder increases the fat content from 21 g to 30 g. What percent does the fat content inc

rease

1 answer:

solong [7]3 years ago

5 0

Answer: 42.9%

Step-by-step explanation:

The percentage increase of the fat content will be calculated as:

= Fat increase / Previous fat content × 100

= (30 - 21) / 21 × 100.

= 9/21 × 100

= 42.9%

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What angle is included by AC and BC?<br> A. B. C.

forsale [732]

Answer:

B

Step-by-step explanation:

3 0

3 years ago

These cylinders are similar. Find the volume of

Basile [38]

Answer:

$V_s=85\ cm^3$

Step-by-step explanation:

Let $V_s\ and\ V_b$ be the volumes of the smaller and bigger cylinder.

The formula for the volume of a cylinder is given by :

$V=\pi r^2 h$

As the two triangles are similar, the cube of their ratio would equal the ratio of their volume i.e.

$\dfrac{V_s}{V_b}=(\dfrac{h_s}{h_b})^3\\\\\dfrac{V_s}{V_b}=(\dfrac{3}{5})^3\\\\\dfrac{V_s}{V_b}=0.216\\\\V_s=393\times 0.216\\\\V_s=84.8\\\\or\\\\V=85\ cm^3$

So, the volume of the smaller cylinder is equal to $85\ cm^3$ .

3 0

3 years ago

Write an expression for the following. "The sum of a number and 12 times 4

andriy [413]

Answer:

4(x + 12)

Step-by-step explanation:

The sum of a number and 12 indicates addition. Then, it says that this sum will be multiplied by 4. So, we can use x to represent this random number.

7 0

3 years ago

Which graph shows the quadratic function y = 3x2 − 12x + 10? (5 points)

eduard

ANSWER

The graph in option D.

EXPLANATION

The given function is:

$y = 3 {x}^{2} - 12x + 10$

We complete the square to obtain:

$y = 3( {x}^{2} - 4x) + 10$

$y = 3( {x}^{2} - 4x + {( - 2)}^{2} ) + 10 - 3 {( - 2)}^{2}$

$y = 3{( x- 2)}^{2}+ 10 - 12$

$y = 3{( x- 2)}^{2} - 2$

The graph of this function opens upwards and has its vertex at (2,-2).

The y-intercept is 10.

From the options the graph that satisfies all these properties is D.

5 0

3 years ago

Find the matrices of

aniked [119]

$\huge{\sf \left[{x-2y\atop 6x-2z}\:\:\:{4y-3\atop 2y-z}\right]=\left[{-3\atop 4}\:\:\:{5\atop 3}\right]}$

Creating equations

$\\ \sf\longmapsto x-2y=-3\dots(1)$

$\\ \sf\longmapsto 4y-3=5\dots(2)$

$\\ \sf\longmapsto 6x-2z=4\dots(3)$

$\\ \sf\longmapsto 2y-z=3\dots(3)$

From eq(2)

$\\ \sf\longmapsto 4y-3=5$

$\\ \sf\longmapsto 4y=5+3$

$\\ \sf\longmapsto 4y=8$

$\\ \sf\longmapsto y=\dfrac{8}{4}$

$\\ \bf\longmapsto y=2$

Put the value in eq(1)

$\\ \sf\longmapsto x-2y=-3$

$\\ \sf\longmapsto x=-3+2y$

$\\ \sf\longmapsto x=-3+2(2)$

$\\ \sf\longmapsto x=-3+4$

$\\ \bf\longmapsto x=1$

Put the value in eq(4)

$\\ \sf\longmapsto 2y-z=3$

$\\ \sf\longmapsto z=2y-3$

$\\ \sf\longmapsto z=2(2)-3$

$\\ \sf\longmapsto z=4-3$

$\\ \bf\longmapsto z=1$

8 0

3 years ago