2.4x10^24/6.022x10^23= 4.00
Answer:
2.173 moles of ethanol is presented in a 100.0g sample of ethanol .
Explanation:
The amount of substance that contains as many Particles as there are atoms in exactly 12g of carbon- '12 isotope is called 1 mole '= 46 u.
Answer:
the mass of CaO present at equilibrium is, 0.01652g
Explanation:
![K_p = [CO_2]](https://tex.z-dn.net/?f=K_p%20%3D%20%5BCO_2%5D)
= 3.8×10⁻²
Now we have to calculate the moles of CO₂
Using ideal gas equation,
PV =nRT
P = pressure of gas = 3.8×10⁻²
T = temperature of gas = 1000 K
V = volume of gas = 0.638 L
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mole.k
Now we have to calculate the mass of CaO
mass = 2.95 * 10 ⁻⁴ × 56
= 0.01652g
Therefore,
the mass of CaO present at equilibrium is, 0.01652g
Molarity
a. Na2CO3
Molar mass = 106 g/mol
n= 109 g / (106 g/mol) = 1.028 mol
b. 6.00L
c. M=n/V
M = 1.028 mol / 6.00 L
M= 0.1713 mol / L
Answer: The molarity of the sodium carbonate solution is 0.1713 mol/L
Answer:
law of multiple proportions
Explanation:
The law of multiple proportions states that, if two elements A and B, combine to form more than one chemical compound. Then the various masses of one element A, which combine separately with a fixed mass of element B are in simple multiple ratio.
We can see that the ratio of oxygen that combines with carbon in the two compounds( A and B) is 1:2. This demonstrates the law of multiple proportions.
The substances A and B must be CO and CO2 respectively.
