Answer:
• It is possible to divide the seventh graders into teams of equal sizes.
,
• 13 students should be on each team.
Explanation:
The seventh grade of Wilson consists of three classes; one with 28 students, one with 29, and one with 34. Therefore, the total number of students in seventh grade is:

He wants each team to have between 4 and 8 students.

Therefore:
• It is possible to divide the seventh graders into teams of equal sizes.
,
• 13 students should be on each team.
Answer:
the rate of change of the area is Ra= 80 mm² per second
Step-by-step explanation:
the area of a rectangle (A) is
A = L * W , L= length and W= width
if the width remains constant the change in the area is only due to the change in length , thus:
ΔA = Δ( L * W ) = W * ΔL , where ΔA represents the change in area and ΔL represents the change in length
ΔA = W ΔL
denoting Δt as the time required to change, and dividing both sides by Δt
ΔA/Δt = W ΔL/Δt
where Ra=ΔA/Δt = rate of change of the area and RL=ΔL/Δt rate of change of the length.
thus
Ra = W * RL
replacing values
Ra = W * RL = 8 mm * 10 mm/second = 80 mm² /second
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Answer: 1 x 10^3
Step-by-step explanation:
The number of stamps with penny in terms of x is 
<em><u>Solution:</u></em>
Given that,
Ryan has x stamps in his collection
Number of stamps of Ryan = x stamps
Let the stamps with penny be "a"
Ryan has 6 times as many stamps as penny
Therefore,
Number of stamps in Ryan = 6 times as many stamps as penny

Thus number of stamps with penny in terms of x is 