All categories

3 years ago

Pls answer ASAP!! its due in 5 hours MY TEACHER DID NOT SHOWUS HOW TO DO THIS PART!!!!! Plsssssssssss HELPPPPPPPPPPPPP

Mathematics

1 answer:

harkovskaia [24]3 years ago

7 0

Answer:

good luck:)

Step-by-step explanation:

You might be interested in

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

4 years ago

All of the following are equivalent, except<br> 3x<br> 2x^2<br> x(2 + 1)<br> 2x + x

Svet_ta [14]

Answer:

2x^2 is not equivalent

Step-by-step explanation:

3x = 3x

2x^2 = 2x^2

X(2+1) = 3x

2x + x = 3x

the odd one out is 2x^2

8 0

3 years ago

Community Gym charges a $50 membership fee and a $70 monthly fee. Workout Gym charges a $190

zepelin [54]

Answer:

14 month

Step-by-step explanation:

Lets create equations for these two gyms. I believe this is an algebra 1 problem.

Community Gym: y=70x+50

Workout Gym: y=60x+190

Because both gyms are equal to y, we can set them together and solve for x.

70x+50=60x+190

10x=140

x=14

You can find the cost by plugging in 14 into both of the equations. You get a cost of $1030 after 14 months

Therefore, after 14 months you will have paid the same amount for both gyms.

7 0

3 years ago

What is the solutiion to this system 3x+2y=8 -x=+y=-11

mr Goodwill [35]

Answer:

2, 19, -3

Step-by-step explanation:

3 0

3 years ago

Which expression is equal to 0?

ahrayia [7]

C if its a question on plato

3 0

3 years ago

Read 2 more answers