To solve for h, you need to isolate/get h by itself in the equation:
s = hp + 2b Subtract 2b on both sides
s - 2b = hp + 2b - 2b
s - 2b = hp Divide p on both sides to get h by itself
![\frac{s-2b}{p} =\frac{hp}{p}](https://tex.z-dn.net/?f=%5Cfrac%7Bs-2b%7D%7Bp%7D%20%3D%5Cfrac%7Bhp%7D%7Bp%7D)
![\frac{s-2b}{p} =h](https://tex.z-dn.net/?f=%5Cfrac%7Bs-2b%7D%7Bp%7D%20%3Dh)
3/1, 2/, 6/, 4/1, hope I helped!
Answer:
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Radical 2 = 1.4 So 1.4 * 6 = 8.4
a^2 + b^2 = c^2
8.4^2 + 8.4^2 = square root of c
70.56 + 70.56 = 141.12 ≈ 141
Then you must find the square root of 141 which is 11.874 ≈ 11.9
Side a = 8.4
Side b = 8.4
Side c = 11.9
Answer:
yes
Step-by-step explanation:
For the relation to be a function, there must only be one corresponding value of y (range) for any value of x in the domain, that is a one-to- one relationship
This graph displays this feature and is a function.