Answer:
4 feet of wall should be on each side of the painting.
Step-by-step explanation:
Given that a 4 foot wide painting should be centered on a 12 foot wide wall, to determine how many feet (X) should be on each side of the painting, the following equation must be solved:
(Total wide of the wall - wide of the painting) / 2 = X
(12 - 4) / 2 = X
8/2 = X
4 = X
Therefore, 4 feet of wall should be on each side of the painting.
Answer:
(a) I attached a photo with the diagram.
(b) 
(c) 1/4
(d) 4
(e) 
Step-by-step explanation:
(a) I attached a photo with the diagram.
(b) The easiest way to think about this part is in terms of combinatorics. Think about it like this.
To begin with, look at the three each level of the three represents a possible outcome of throwing the coin n-times. If you throw the coin 3 times at the end in total there are 8 possible outcomes. But The favorable outcomes are just 2.
1 - Your first outcome is HEADS and all the others are different except the last one.
2 - Your first outcome is TAILS and all the others are different except the last one.
Therefore the probability of the event is

(c)
P(X = 0) = 0 because it is not possible to have two consecutive tails or heads.

(d)
Remember that this is a geometric distribution therefore
, in this case
so
and
![E[X+1]^2 = ( E[X] +1 )^2 = (1+1)^2 = 2^2 = 4](https://tex.z-dn.net/?f=E%5BX%2B1%5D%5E2%20%3D%20%28%20E%5BX%5D%20%2B1%20%29%5E2%20%20%3D%20%281%2B1%29%5E2%20%3D%202%5E2%20%3D%204)
Also
(e)
This is a geometric distribution so its variance is

And using properties of variance

Answer:
make shur your using fractions
54 60
x 100 cross multiply
54(100) 60(x)
5400 60x
divided both by 60
5400/60 60/60
90 1
= $90
then you go
54 60
90 100
and use a caculater to see if your answer is coorect
you just fowllow the steps to see if you get 90
Step-by-step explanation:
Answer:
44.8 %
Step-by-step explanation:
Let p = the number of people. Then
Total biocapacity = 6.21p ha
Grazing biocapacity = 0.85p ha
Forest biocapacity = <u>2.53p </u>
Grazing + forest = 2.78p ha
