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S_A_V [24]
3 years ago
15

Which strategy best explains how to solve this problem? Apples cost $1.25 per pound. Oranges cost $1.49 per pound. Krystal wants

to buy 3 pounds of apples and some oranges. She has $10.00 to spend. How many pounds of oranges can Krystal buy? A. Make a double bar graph. Graph $1.25 using one color and $1.49 using another color. Then graph the cost of 2 pounds of each fruit, then graph the cost of 3 pounds of each fruit. Keep graphing until one of the costs is more than $10. B. Make a table. Write 1, 2, 3, 4, 5, 6, 7, 8 (the number of pound of oranges) on the top row and write the total cost of the apples ($1.25 × 3) in every box on the second row. Fill out the cost of 1, 2, 3, 4, 5, 6, 7, 8 pounds of oranges on the third row and the total cost on the bottom row. The correct answer is the number of pounds of oranges that can be purchased that makes the total cost closet to $10, but not more than $10. C. Draw a diagram. Draw 10 boxes to represent the $10 Krystal has. Draw an apple in 3 of the boxes to show the 3 pounds of apples Krystal will buy. Count the number of empty boxes to determine the number of pounds of oranges Krystal can buy.
Mathematics
1 answer:
ValentinkaMS [17]3 years ago
6 0
The best strategy is to use the tables in this example. The tables will give an exact cost for an exact number of apples or oranges. You can then use these pieces of information to determine which number of apples and oranges will get you closest to $10.

The diagram strategy is not accurate based on the information.

The double bar graph is also not going to work because the two pieces of information are related, so you would not create a separate bar for the price and the number of apples.
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Previous concepts

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Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,0.08)  

Where \mu and \sigma=0.08

Since the distribution for X is normal then the  we know that the distribution for the sample mean \bar X is given by:

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