a. Let
be a random variable representing the weight of a ball bearing selected at random. We're told that
, so

where
. This probability is approximately

b. Let
be a random variable representing the weight of the
-th ball that is selected, and let
be the mean of these 4 weights,

The sum of normally distributed random variables is a random variable that also follows a normal distribution,

so that

Then

c. Same as (b).
Solve and the solution would be (-1, 2)
x value = -1
Answer:
it is b
Step-by-step explanation:
hope i helped
Hello.
To get the volume 5184 in3 you can use the dimension 18in x 24in x 12in.
First, you should draw a picture of your shipping container. It is a rectangular prism that is 5 by 12 by 4.
Next, let's look at the boxes of apples that will go into the box. The volume has to be 5184 in^3. If we divide it by 12 and 12, the answer is 3. Therefore, we could make a box that is 1 foot by 1 foot by 3 feet.
Those boxes would be stack on the base without any left over space. Now, just figure out how many would go on the next rows. They would be able to stand up and down.
Have a nice day.
5 -> 15
6 -> 20
7 -> 25
8 -> 30
9 -> 35
10 -> 40
then in ones:
after 41 would be 42 and 43
the elapsed time would be 43 minutes :)
hope this helps :)