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3 years ago

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Mathematics

1 answer:

Monica [59]3 years ago

5 0

Answer:

Interest earned = $32.835

Step-by-step explanation:

Given the following data;

Principal = $275

Number of times = 0.5

Interest rate = 2.9% = 0.029

Time = 4 years

To find the interest earned, we would use the compound interest formula;

$A = P(1 + \frac{r}{n})^{nt}$

Where;

A is the future value.

P is the principal or starting amount.

r is annual interest rate.

n is the number of times the interest is compounded in a year.

t is the number of years for the compound interest.

Substituting into the equation, we have;

$A = 275(1 + \frac{0.029}{0.5})^{0.5*4}$

$A = 275(1 + 0.058)^{2}$

$A = 275(1.058)^{2}$

$A = 275(1.1194)$

A = $307.835

Interest earned = 307.835 - 275

Interest earned = $32.835

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Need some math help thanks in advance!

vredina [299]

Answer:

x = 10

y = 6

Step-by-step explanation:

<u>Vertical Angle Theorem</u>: When two straight lines intersect, the opposite vertical angles are always equal to each other.

⇒ m∠1 = m∠3 and m∠2 = m∠4

⇒ m∠1 = m∠3

⇒ 10x = 100

⇒ x = 10

<u>Linear pair:</u> Two adjacent angles which sum to 180°.

⇒ m∠1 + m∠2 = 180°

⇒ m∠3 + m∠4 = 180°

⇒ 100 + 10y + 20 = 180

⇒ 120 + 10y = 180

⇒ 10y = 60

⇒ y = 6

7 0

2 years ago

A video game is on sale for 40% off. The sale price is $34.79. Find the original price of the game.

makkiz [27]

6”5 dollars is the answe

5 0

3 years ago

I need help with this asap

dedylja [7]

I got no solution i might be wrong tho

4 0

2 years ago

Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.

borishaifa [10]

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 14, p = 0.8$

P(x>10)

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501$

$P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501$

$P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539$

$P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440$

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981$

So P(x > 10) = 0.6981.

8 0

3 years ago

Bacteria of species A and species B are kept in a single environment, where they are fed two nutrients. Each day the environment

DiKsa [7]

Answer:

We require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

Step-by-step explanation:

Let n₁ be the population of A required and n₂ be the population of B required.

Now we require 2 units of the first nutrient for species A and one unit of the first nutrient for species B. The total nutrients required by species A is 2n₁ and that by species B is 1n₂ = n₂. So, the total nutrients required by both species A and B is 2n₁ + n₂. Since this equals the quantity of the first nutrient which is 10,560, then 2n₁ + n₂ = 10,560 (1)

Now we require 5 units of the second nutrient for species A and 6 units of the second nutrient for species B. The total nutrients required by species A is 5n₁ and that by species B is 6n₂. So, the total nutrients required by both species A and B is 5n₁ + 6n₂. Since this equals the quantity of the first nutrient which is 31,510, then 5n₁ + 6n₂ = 31,510 (2).

So, we have two simultaneous equations which we would solve to find the populations of A and B which satisfy both equations.

2n₁ + n₂ = 10,560 (1)

5n₁ + 6n₂ = 31,510 (2)

From (1) n₂ = 10,560 - 2n₁ (3)

Substituting equation (3) into (2), we have

5n₁ + 6(10,560 - 2n₁) = 31,510

expanding the brackets, we have

5n₁ + 63,360 - 12n₁ = 31,510

collecting like terms, we have

5n₁ - 12n₁ = 31,510 - 63,360

simplifying, we have

- 7n₁ = -31,850

dividing both sides by -7, we have

n₁ = -31,850/-7

n₁ = 4,550

Substituting n₁ = 4,550 into (3), we have

n₂ = 10,560 - 2(4,550)

n₂ = 10,560 - 9,100

n₂ = 1,460

So, we require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

3 0

2 years ago