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Ilya [14]
2 years ago
14

Plz help me with this

Mathematics
1 answer:
zvonat [6]2 years ago
8 0

Answer:  5 cos x

<u>Step-by-step explanation:</u>

y = sin x     is       y = cos x        shifted to the right π/2 units.

y = 5 sin (x + π/2)     is a shift to the left π/2 units (which results in cos x) and    .                                 an amplitude of 5.

--> y = 5 cos x

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Answer: How much paint

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2 years ago
What does 18 tens and 20 ones equal
Rudiy27
18 tens= 180
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200
6 0
2 years ago
Read 2 more answers
WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7
Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0
2 years ago
Which of the following points is the solution of the quadratic equation:3x^2-5x-2=0​
Maslowich

Answer:

x1 = 2

x2 = -1/3

Step-by-step explanation:

3x^2-5x-2=0

D=25-4*(-2)*3 = 25 + 24 = 49 --> sqrt 49 = 7

x1 = 5 + 7 / 2*3 =   2

x2 = 5 - 7 / 2*3 =  -1/3

7 0
2 years ago
P is the midpoint of ad aq:qb=2:3 show that pq is parallel to cb
sveticcg [70]

Answer:

question a) is 2q+3p

Step-by-step explanation:

4 0
3 years ago
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